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taurus [48]
3 years ago
9

Given: ABCD is a rhombus, Perimeter = 20, AC:BD = 4:3 Find: Area of ABCD.

Mathematics
1 answer:
REY [17]3 years ago
6 0
4a=20⇒a=5

we know diagonals are perpendicular. if u look at one of the right triangles, you can see that for hypotenuse to be 5, the legs have to be 4 and 3 to satisfy the given ratio 4:3.

so, diagonals are 8 and 6 as we know that diagonals bisect each other.

Area=8*6/2=24
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Maths easy class 8 whoever gets it I will give u brainlist​
asambeis [7]

Answer:

424 cm²

Step-by-step explanation:

The figure is composed of a square and a trapezium on top

A of square = 18² = 324 cm²

A of trapezium = \frac{1}{2} h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 8, b₁ = 18 and b₂ = 7 , then

A = 0.5 × 8 × (18 + 7) = 4 × 25 = 100 cm²

Area of hexagonal park = 324 + 100 = 424 cm²

8 0
3 years ago
I did 3 over 7 then 8 over x. I'm getting decimals. ‍♀️
julia-pushkina [17]

Answer:

The length of side <em>b</em> is 9.

Step-by-step explanation:

Triangles are similar if they have the same shape, but can be different sizes.

When two figures are similar, the ratios of the lengths of their corresponding sides are equal.

If you know that two objects are similar, you can use proportions and cross products to find the length of an unknown side. We know that the triangle ABC is similar to the triangle XYZ. Therefore the following relation must be true:

                                                      \frac{AB}{AC} =\frac{XY}{XZ}

We know that side AB is equal to 8, side AC is equal to <em>b, </em>side XY is equal to 2\frac{2}{3}, and side XZ is equal to 3.

Substituting these values into the above relation and solving for <em>b</em> we get that:

\frac{8}{b} =\frac{2\frac{2}{3} }{3}\\\\\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{2}{3}=\frac{8}{3}\\\\\frac{8}{b}=\frac{\frac{8}{3}}{3}\\\\8\cdot \:3=b\frac{8}{3}\\\\24=b\frac{8}{3}\\\\8b=72\\\\b=9

5 0
3 years ago
3 over 50 as a decimal
Artemon [7]
 3 over 50

= 3/50        Multiply top and bottom by 2

= (3/50)*(2/2) = 6/100

= 0.06


8 0
3 years ago
The track team won a total of 18 medals. Three of the medals were gold. There were twice as many bronze medals as silver medals.
monitta
10 bronze medals

explaining:
if 3 of the medals were gold there would be 15 left. Since there was twice as many bronze from silver they would have 5 silver medals and 10 bronze.
4 0
3 years ago
Write an equation in slope-intercept form for the line with slope -7 and y-intercept 9. Then graph the line.
Arisa [49]
Y= -7x +9 to graph plot point (0,9) and then go down 7 and to the right 1 (plot another point and connect line)
6 0
4 years ago
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