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Vlad1618 [11]
3 years ago
6

What is the radius of the circle? Example how you know..

Mathematics
2 answers:
Lostsunrise [7]3 years ago
7 0

Answer:

The radius of the circle is 7 units.

Step-by-step explanation:

Radius is the measure from the center point of a circle to a point on the outside edge. Since you have coordinates, you can find the radius using distance formula.

<em>You could also just count how many units are between the center and the edge to get 7 units because 8 - 1 = 7</em>

xxTIMURxx [149]3 years ago
3 0

Answer:

r=7

Step-by-step explanation:

C is at x=1 at circle side is at 8

8-1= 7

so, r=7

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Kay [80]
The corrrct answer is x= -1

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3 years ago
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Lolita deposited 500 in her savings account that earns 5% intrest compounded anually. She forgot about it until now, 15 years la
Sonja [21]

Answer:

P = 1039.5

Step-by-step explanation:

Given:-

- The initial amount deposited, Po = 500

- The interest rate applied, I = 5% compounded annually

Find:-

- The amount on her bank statement after 15 years?

Solution:-

- We see that the principal amount increases every year and no transactions have been made in the course of 15 years.

The total amount left in her savings account would be given by the following formula:

                         P = Po * ( 1 + I/100 )^n

- Where, n = number of years passed since deposit. (15 years)

                        P = 500 * ( 1 + 5/100 )^15

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6 0
2 years ago
NEED HELP ASAP!!
Solnce55 [7]

Answer:

Only Cory is correct

Step-by-step explanation:

The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;

F =G\times \dfrac{M \cdot m}{r^{2}}

Where;

G = The universal gravitational constant

M = The mass of one object

m = The mass of the other object

r = The distance between the centers of the two objects

For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km

Therefore, for an astronaut in the international Space Station, r = 6,800 km

The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;

\dfrac{F_1}{F_2} = \dfrac{ \dfrac{M \cdot m}{R^{2}}}{\dfrac{M \cdot m}{r^{2}}} = \dfrac{r^2}{R^2}  = \dfrac{(6,800 \ km)^2}{(6,371 \ km)^2} \approx  1.14

∴ F₁ ≈ 1.14 × F₂

F₂ ≈ 0.8778 × F₁

Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth

However, the International Space Station is moving in its orbit around the Earth at an orbiting speed enough to prevent the Space Station from falling to the Earth such that the Space Station falls around the Earth because of the curved shape of the gravitational attraction, such that the astronaut are constantly falling (similar to falling from height) and appear not to experience gravity

Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.

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