La respuesta es 6.92 en su expresión más pequeña porque dice la altura de un triángulo equilátero es igual solo sacas las fórmula de la altura de un triángulo que es a^2=c^2+B^2 osea haci que sustituye con valores h^2= 8^2-4^2=h^2 8x8=64 4x4=16 64-16= √48 = 6.92

8 0

3 years ago

Given that X ~ N(120, 35). We survey samples of 25 and are interested in the distribution of X-bar. Find the z-score associated

lubasha [3.4K]

Answer:

Option c -2.8571

Step-by-step explanation:

z-score are calculated as

$z=\frac{xbar-mean}{\frac{S.D}{\sqrt{n} } }$ .

We are given that mean=120 and standard deviation=S.D=35 as X~N(120,35).

Sample size=n=25.

We have to find z-score for x-bar=100. So,

z-score=[100-120]/[35/√25]

z-score=[-20]/[35/5]

z-score=-20/7

z-score=-2.8571.

Thus, the z-score associated with x-bar = 100 is -2.8571.

8 0

3 years ago

The perimeter of an isosceles triangle is 1 m, and the length of the base is equal to 0.4 m. Find the length of a leg.​

The perimeter of an isosceles triangle is 1 m, and the length of the base is equal to 0.4 m. Find the length of a leg.