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klio [65]
3 years ago
7

Help please.............

Mathematics
2 answers:
Aleksandr [31]3 years ago
5 0

Answer:

10 C

Step-by-step explanation:

Kruka [31]3 years ago
4 0

Answer: D Or 10

Step-by-step explanation: Because If you subtract 50 by 32 you will get 18 and then you get 5/9(18) and then you can cross simplify which gets you 5x2 which is 10.

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Helppp plzzzzz mathhh
spayn [35]

Answer:

A) f^-1(x)=(x-8)^3+2

Step-by-step explanation:

To find the function inverse, switch the x with y and solve for y.

y=\sqrt[3]{x-2}+8 \\\\x=\sqrt[3]{y-2}+8\\\\(x-8)^3 = y-2\\\\ (x-8)^3 + 2 = y

5 0
3 years ago
what number must be added to 3 and 8 so that the ratio of the first number to the second number is equal to 3 :4​
Grace [21]
The answer is 12.
Steps
If that number is x
(3+x)/(8+x)=3/4
"Cross multply"
4(3+x)=3(8+x)
12+4x=24+3x
x=12
To check: add 12 to 3 and 8. 3+12=15 and 8+12=20. 15/20=3/4
3 0
3 years ago
Type the slope-intercept equation
natulia [17]

Answer:

y= -2x +1

Step-by-step explanation:

<u>slope- intercept form</u><u>:</u>

y= mx +c, where m us the gradient and c is the y-intercept.

Let's find the value of m first using the gradient formula.

Gradient= \frac{y1 - y2}{x1 - x2}

m =  \frac{ - 3 - 3}{2 - ( - 1)}  \\ m =  \frac{ - 6}{2 + 1}  \\ m =  \frac{ - 6}{3}  \\ m =  - 2

y= -2x +c

To find the value of c, substitute a pair of coordinates.

When x= -1, y=3,

3= -2(-1) +c

3= 2 +c

c= 3 -2

c= 1

Thus the equation of the line is y= -2x +1.

4 0
2 years ago
Can you please help me solve
Digiron [165]

Answer:

First Problem:

1/2 * -2 2/5 = 1/2 * -12/5 = -12/10

Simplify -12/10 into -6/5

Step-by-step explanation:

8 0
3 years ago
Kim had 160 cards in a box.She gave 4/10 of the cards to maddy.How many cards did Kim have left in the box
Marysya12 [62]
\text {Total cards = 160}

\text {Cards gave to Maddy = }  \dfrac{4}{10}  \times 160 = 64&#10;

\text {Cards left = } 160 - 64 = 96&#10;&#10;

------------------------------------
Answer: Cards left = 96 
------------------------------------
4 0
3 years ago
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