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Bingel [31]
3 years ago
7

Can you find the lengths and areas and type the correct code? Please remember to type in ALL CAPS with no spaces. *

Mathematics
1 answer:
Virty [35]3 years ago
3 0

Step-by-step explanation:

1.  156.15

2.  12335.85

3. 182.33

4. 8934.17

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Review
garri49 [273]

Answer:

1.32

Step-by-step explanation:

we have the known,

2.13 km * 0.6214 miles = 1.323521 or 1.32 miles

                      1 km  

4 0
3 years ago
What’s the correct answer for this question?
Damm [24]

Answer:

tan C = 3/4

Step-by-step explanation:

sin C = opposite over hypotenuse

sin C = 3/5

BC = 5

AB = 3

We can use the Pythagorean theorem

a^2 + b^2 = c^2

3^2 + b^2 = 5^2

9 + b^2= 25

Subtract 9 from each side

9-9+b^2=25-9

b^2= 16

Take the square root of each side

sqrt(b^2)= sqrt(16)

b = 4

AC = 4

Tan C = opp side/ adj side

tan C = AB/ AC = 3/4

5 0
3 years ago
Read 2 more answers
The weights of cars passing over a bridge has a mean of 3550 lb and a standard deviation of 870 lb. Assume that the weights of t
elena-s [515]

Step-by-step explanation:

Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs.  So choose appropriate answer accordingly (near the end)

Using the usual notations and formulas,

mean, mu = 3550

standard deviation, sigma = 870

Observed value, X = 3000

We calculate

Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839

Probability of weight below 3000 lbs

= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334

Answer:

Probability that a car randomly selected is less than 3000

= P(X<3000) = 0.2636 (to 4 decimals)

Probability that a car randomly selected is greater than 3000

= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)

5 0
3 years ago
Read 2 more answers
A quadratic equation ax^2+bx+c=0 has -11 and 4 as solutions. Find the values of b and c if the value of a is 1 (hint, use zero f
Alina [70]

Answer:

b = 7, c = -44

Step-by-step explanation:

If the quadratic equation has the solutions -11 and 4, the two factors are:

(x+11)(x-4)=0

Since when we use the zero factor property we get

x+11=0 ⇒ x= -11

x-4=0 ⇒  x=4

Thus, we have used the zero factor property in reverse to find the factorization of the quadratic equation.

Now we develop the multiplications between parenthesis:

(x+11)(x-4)=0\\x^2-4x+11x-44=0\\x^2+7x-44=0

So b is the number that accompanies the x: b = 7

and c is the independent number: c = -44

3 0
3 years ago
Choose the correct description of the graph of the compound inequality
Vikki [24]
A number line with a closed circle on-2, an open circle on 5, and shading in between so the answer C. is correct
5 0
3 years ago
Read 2 more answers
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