Width of the miniature model =
inches
Length of the miniature model =
inches
The actual width of the boat = 15 feet
Let us find the actual length of the boat.
Write it in a proportion form.
width of model : length of model : : width of actual : length of actual



Do cross multiplication.



⇒ x = 22
Hence the actual length of the boat is 22 feet.
Answer:
The rocket hits the ground at a time of 11.59 seconds.
Step-by-step explanation:
The height of the rocket, after x seconds, is given by the following equation:

It hits the ground when
, so we have to find x for which
, which is a quadratic equation.
Finding the roots of a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:



In this question:


So




Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.
D. -12
Lol I think I've explained this enough times now so you know the process
Answer:
It would be C since a scale factor of 2 makes the original A coordinate of (3,3) times 2 therefore the new coordinates being (6,6)
Step-by-step explanation:
Answer:
L = 3(4) + 2(3) + 6
Step-by-step explanation:
.........