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strojnjashka [21]
2 years ago
11

Find the x-intercept and y-intercept of the line. 3x + y = 6

Mathematics
1 answer:
Dafna1 [17]2 years ago
6 0

Answer:

x = (6 - y)÷ 3

Step-by-step explanation:

3x + y = 6

3x = 6 - y

x = 6 - y ÷ 3

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Can someone answer this plz (-2z^2-14)-(-12z^2)
Orlov [11]

Answer:

\large\boxed{(-2z^2-14)-(-12z^2)=10z^2-14}

Step-by-step explanation:

(-2z^2-14)-(-12z^2)=-2z^2-14+12z^2\qquad\text{combine like terms}\\\\=(-2z^2+12z^2)-14=10z^2-14

8 0
3 years ago
Can someone help me with this? And please, actually try with this one.
SashulF [63]

Answer:

32/3 or 10.6 repeating

Step-by-step explanation:

multiply by reciprocal

6*(16/9)

96/9

simplified to 32/3

4 0
2 years ago
Read 2 more answers
This is correct right?
lubasha [3.4K]

Answer:

Yes, it is not a diameter

Step-by-step explanation:

It's going through the circle (sphere) which makes it a diameter

I and D are not going straight through the middle

6 0
2 years ago
Read 2 more answers
Solve -2/3x > 8 or -2/3x < 4.
vekshin1
<h3>Answer: Choice C</h3>

{x | x < -12 or x > -6}

=========================================================

Explanation:

Let's solve the first inequality for x.

(-2/3)x > 8

-2x > 8*3

-2x > 24

x < 24/(-2)

x < -12

The inequality sign flips when we divide both sides by a negative value.

Let's do the same for the second inequality.

(-2/3)x < 4

-2x < 4*3

-2x < 12

x > 12/(-2)

x > -6

The conclusion of each section is that x < -12 or x > -6 which points us to <u>choice C</u> as the final answer.

Side note: The intervals x < -12 and x > -6 do not overlap in any way. There's a gap between the two pieces. We consider these intervals to be disjoint. The number line graph is below.

8 0
2 years ago
[Algebra 2] Find the quotient with the necessary restrictions.​
Tatiana [17]

Answer:

The correct answer is:   3x² (4x - 1) / (x - 4) (x - 3) ∧ restriction x ≠ 3, x ≠ 4, x ≠ 0 and x ≠ 1/4

Step-by-step explanation:

Given:

((16x² - 8x + 1) / (x² - 7x + 12)) : ((20x² - 5x) / 15x³) =

dividing with one fraction is the same as multiplying with its reciprocal value

((16x² - 8x + 1) / (x² - 7x + 12)) · (15x³ / (20x² - 5x))

First we need to factorize both numerators and denominators

16x² - 8x + 1 = (4x - 1)²   This is square binomial

x² - 7x + 12 = x² - 4x - 3x + 12 = x (x - 4) - 3 (x - 4) = (x - 4) ( x - 3)

20x² - 5x = 5x (4x - 1)

(4x - 1)² / (x - 4) (x - 3) ·  15x³ / 5x (4x - 1)

The existence of this rational algebraic expression is possible only if it is:

x - 4 ≠ 0 and x - 3 ≠ 0 and x ≠ 0 and 4x - 1 ≠ 0  =>

x ≠ 4 and x ≠ 3 and x ≠ 0 and x ≠ 1/4  This is restriction

Finally we have:

3 x² (4x - 1) / (x - 4) (x - 3)

God with you!!!

8 0
3 years ago
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