Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
3 more than 7= 7 +3 3 added to 7= 7 +3 lesson 1-6... five plus x minus 3 2) three times y less 4 3).. seven minus twice the quotient of x and 3
They sold 17 rolls. Because:
$4×45= 180
$265-180= 85
85÷5= 17
When x = 0, the value of f(x) is 2. You can see why below
f(x) = (2^x) + 1
f(0) = (2^0) + 1
f(0) = 1+1
f(0) = 2
So the point (0,2) is on the curve. This is visually shown as the y intercept (the location where the curve crosses the y axis)
When x = 2, the value of f(x) is 5
f(x) = (2^x) + 1
f(2) = (2^2) + 1
f(2) = (4) + 1
f(2) = 5
So (2,5) is another point on this curve
Find the slope of the line through these two points
m = (y2 - y1)/(x2 - x1)
m = (f(2) - f(0))/(2 - 0)
m = (5 - 2)/(2 - 0)
m = 3/2
m = 1.5
The slope as a fraction is 3/2
The slope as a decimal is 1.5
So the rate of change is 1.5
