Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E
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Work Shown
Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A
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Problem 47)
If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago
So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B
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Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
Equilateral is all angles are equal and isosceles has two equal sides
There is no question here to answer.
Group is the answer I think
Answer:
Step-by-step explanation:
Here the number of variables is 2
Variable x should be the number of 100 pound bags of lawn fertilizer to be made.
Variable y should be the number of 100 pound bags of garden fertilizer to be made.
The number of constraints is 5
They are,
0.35x + 0.14y ≤ 160 ----(1)
0.20x + 0.13y ≤ 220 ----(2)
0.20x + 0.12y ≤ 140 ----(3)
x ≥ 0 ----(4)
y ≥ 0 ----(5)
The number of objective functions is 1
It is, Maximize Z = 15x + 10y
