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Umnica [9.8K]
3 years ago
14

20 plants were mesured and their heights recorded in cm. here are the heights: 13.2 17 4.8 15.6 12 8.5 11.1 9.9 17.4 14.7 12.6 7

.7 13.5 14 9.5 9.8 10 11.3 6.9 5. complete the frequency tabel.
Mathematics
1 answer:
GaryK [48]3 years ago
7 0

Answer:

hi there I have.

Step-by-step explanation:

the train leaves at 6.30. unfortunately the flight is delayed.

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Given f(x) = 3x^3 - 4x^2 + x - 1 , what is f(2) ?
Yakvenalex [24]
2 will replace each x on the right

3•(2^3) - 4•(2^2) + 2 -1
3•8 - 4•4 + 1
24 - 16 + 1
8+1
9
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3 years ago
You want to put $2,500 in a simple interest account.It has a 4% annual interest rate.How long will it take you to earn $200 in i
prohojiy [21]
It will take 2 years.

Year 1 :
4% 2.5k = 2.5k/100 × 4 = $100 in interest

$2.5k + $0.1k = $2.6k

Year 2 :
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7 0
3 years ago
Captain's Autos sells 22 used cars on
aliina [53]

Answer:

160

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3 0
1 year ago
Level 4
nignag [31]

132/4 = 33, x = 33 boxes

6 0
3 years ago
Read 2 more answers
If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b
Readme [11.4K]

Answer:

  • Exact distance = 90\sqrt{2} feet
  • Approximate distance = 127.2792 feet.

===========================================================

Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\

The distance from 1st to 3rd base is roughly 127.2792 feet.

5 0
2 years ago
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