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2 years ago

N = 3(k + m)Solve for m

Mathematics

2 answers:

Minchanka [31]2 years ago

8 0

n = 3(k+m)

n = 3k + 3m

3m = -3k + n

m = -k + 1/3 n

Natali5045456 [20]2 years ago

6 0

Answer:

m = (n/3) - k

Step-by-step explanation:

n = 3(k + m)

n = 3k + 3m

n - 3k = 3m

3m/3 = (n - 3k)/3

m = (n/3) - k

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3 years ago

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Help on this one please??

xenn [34]

Answer:

C = ~50 deg

Step-by-step explanation:

Apply the cosine theorem:

cos(C) = (CA^2 + CB^2 - AB^2)/(2*CA*CB)

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3 years ago

For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?

konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

$x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)$

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

$From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1$

After solving we get value of y=-1

Now putting in eq(1) to get value of x

$x+2y=0\\x+2(-1)=0\\x-2=0\\x=2$

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

$5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3$

So, After solve the equations we get value of k=3

4 0

3 years ago

Can anyone heelp me pls

avanturin [10]

Answer:

I think it's b.

Step-by-step explanation:

b. ,. ....

7 0

3 years ago

N = 3(k + m)Solve for m​

N = 3(k + m)Solve for m