Find the equation of the line perpendicular to
tle="-\frac{1}{2} x" alt="-\frac{1}{2} x" align="absmiddle" class="latex-formula"> and passing through the point (−6; 1).
2 answers:
The slope is 2x
Y-1=2(x+6)
Y=2x+13 is the answer
⦿ Hi There! ⦿
Point-Slope form:
y-y1=m(x-x1)
y-1=m(x-(-6)
Perpendicular lines have slopes that are opposite reciprocals.
It means that if we have -1/2, we flop it over and make it positive.
So the slope of the new line is 2.
y-y1=m(x-x1)
y-1=2(x-(-6)
y-1=2(x+6)
y=1=2x+12
y=2x+12-1
<u>y=2x+11</u>
Hope it helps!
~Just a cheerful gal
#CarryOnLearning
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