Answer:
Step-by-step explanation:
Anything that is horizontal is a 0-slope. So take a pen for example if you put it on its side it is a 0-slope.
Answer:
![x=\frac{1}{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B3%7D)
Step-by-step explanation:
move the terms with
to the left side of the equation:
add 3x to both sides
![3x-1+3x=1](https://tex.z-dn.net/?f=3x-1%2B3x%3D1)
add 3x and 3x
![6x-1=1](https://tex.z-dn.net/?f=6x-1%3D1)
move all term not containing
to the right side:
add 1 to both sides of the equation
![6x=1+1](https://tex.z-dn.net/?f=6x%3D1%2B1)
![6x=2](https://tex.z-dn.net/?f=6x%3D2)
divide each term by 6
![\frac{6x}{6}=\frac{2}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B6x%7D%7B6%7D%3D%5Cfrac%7B2%7D%7B6%7D)
![x=\frac{2}{6}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%7D%7B6%7D)
simplify the fraction
![x=\frac{1}{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B3%7D)
Answer:
![\tan \theta = - \frac{1}{5} = - 0.2](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D%20-%20%5Cfrac%7B1%7D%7B5%7D%20%3D%20-%200.2)
![\cos \theta = 0.98](https://tex.z-dn.net/?f=%5Ccos%20%5Ctheta%20%3D%200.98)
![\sin \theta = - 0.196](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%20%3D%20-%200.196)
Step-by-step explanation:
It is given that
and
is in the fourth quadrant.
So, only
will have positive value and
,
will have negative value.
Now, ![\cot \theta = - 5](https://tex.z-dn.net/?f=%5Ccot%20%5Ctheta%20%3D%20-%205)
⇒
(Answer)
We know, that ![\sec^{2} \theta - \tan^{2} \theta = 1](https://tex.z-dn.net/?f=%5Csec%5E%7B2%7D%20%5Ctheta%20-%20%5Ctan%5E%7B2%7D%20%5Ctheta%20%3D%201)
⇒
{Since,
is positive then
will also be positive}
⇒
(Answer)
We know, that ![\csc^{2} \theta - \cot^{2} \theta = 1](https://tex.z-dn.net/?f=%5Ccsc%5E%7B2%7D%20%5Ctheta%20-%20%5Ccot%5E%7B2%7D%20%5Ctheta%20%3D%201)
⇒
{Since,
is negative then
will also be negative}
⇒
(Answer)
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First way
arcsin(1/4) means that 1/4 sin of the angle.
sin(α)=1/4
sin²α+cos²α=1
(1/4)²+cos²α=1
cos²α=1-1/16 =15/16
cosα=+/-(√15)/4
<span>Second way
</span>
sin(α)=1/4 =opposite leg/hipotenuse
cos(α)=adjacent leg/hypothenuse
adjacent leg =√(hypotenuse²- Opposite²)=√(16-1)=√15
cosα=+/-√15/4
For one value of sinα, possible 2 values of cosα.