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Alekssandra [29.7K]

2 years ago

5

(03.01 LC) What is the length of leg y of the right triangle? (1 point)

1 answer:

EastWind [94]2 years ago

4 0

Answer:

<h2>A</h2>

Step-by-step explanation:

The complete question is

What is the length of leg y of the right triangle?

A right triangle with hypotenuse 26 and legs 24 and y

10
14
24
26

We need to use the Pythagorean Theorem, where $h=26$ and $x=24$ ,

$h^{2} =x^{2} +y^{2}\\ 26^{2}=24^{2}+y^{2}\\y=\sqrt{26^{2}-24^{2}}\\ y=\sqrt{676-576}\\ y=\sqrt{100}\\ y=10$

Therefore, the right answer is A. The length of the missing leg is 10 units.

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Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)

Artemon [7]

Answer:

The coordinates of $M$ are $x = \frac{15}{2}$ and $y = 1$ .

Step-by-step explanation:

Let be $A = (-3,-6)$ and $B = (12, 4)$ endpoints of segment AB and $M$ a point located 7/10 the way from A to B. Vectorially, we get this formula:

$\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}$

$\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)$

By Linear Algebra we get the location of $M$ :

$\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)$

$\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A$

$\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot \vec B$

If we know that $\vec A = (-3,-6)$ and $\vec B = (12, 4)$ , then:

$\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)$

$\vec M = \left(-\frac{9}{10},-\frac{9}{5} \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)$

$\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5} \right)$

$\vec M = \left(\frac{15}{2} ,1\right)$

The coordinates of $M$ are $x = \frac{15}{2}$ and $y = 1$ .

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Answer:

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Step-by-step explanation:

The answer is 3,9,15,21.

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