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3 years ago

The measure of ∠1 = 188 172 94

Mathematics

1 answer:

yanalaym [24]3 years ago

4 0

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

There is a cyclic quadrilateral.

As we know that "Sum of opposite angles in a cyclic quadrilateral is supplementary.":

so, it becomes,

$86^\circ+\angle 1=180^\circ\\\\\angle 1=180^\circ-86^\circ\\\\\angle 1=94^\circ$

Hence, the measure of ∠1 = 94°

Therefore, Third option is correct.

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How many triangles and quadrilaterals altogether can be formed using the vertices of a 7-sided regular polygon?

MAVERICK [17]

Answer: The correct option is

(E) 70.

Step-by-step explanation: We are given to find the number of triangles and quadrilaterals altogether that can be formed using the vertices of a 7-sided regular polygon.

To form a triangle, we need any 3 vertices of the 7-sided regular polygon. So, the number of triangles that can be formed is

$n_t=^7C_3=\dfrac{7!}{3!(7-3)!}=\dfrac{7\times6\times5\times4!}{3\times2\times1\times4!}=35.$

Also, to form a quadrilateral, we need any 4 vertices of the 7-sided regular polygon. So, the number of quadrilateral that can be formed is

$n_q=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.$

Therefore, the total number of triangles and quadrilaterals is

$n=n_t+n_q=35+35=70.$

Thus, option (E) is CORRECT.

8 0

3 years ago

Round number 245-320

Vesnalui [34]

Answer:

300

Step-by-step explanation:

if you mean, 245.320

5 0

2 years ago

What is the answer about this I really need help

sergey [27]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Suppose we want to choose colors, without replacement, from the colors red, blue, green, and purple.

DerKrebs [107]

The number of ways when the choice is not relevant is 4

<h3>How to determine the number of ways?</h3>

The number of colors are:

Colors, n = 4

The color to choose are:

r = 3

<u>Relevant choice</u>

When the choice is relevant, we have:

$Ways = ^nP_r$

This gives

$Ways = ^4P_3$

Evaluate

Ways = 24

Hence, the number of ways when the choice is relevant is 24

<u>Not relevant choice</u>

When the choice is not relevant, we have:

$Ways = ^nC_r$

This gives

$Ways = ^4C_3$

Evaluate

Ways = 4

Hence, the number of ways when the choice is not relevant is 4