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3 years ago

7. Suppose a parabola has vertex (-4,7) and also passes through the point (-3,8). What is the equation

Mathematics

1 answer:

WINSTONCH [101]3 years ago

6 0

9514 1404 393

Answer:

(a) y=(x+4)^2 +7

Step-by-step explanation:

The vertex form equation is ...

y = a(x -h)^2 +k

for vertex (h, k) and vertical scale factor 'a'.

The vertex is given as (h, k) = (-4, 7), so the equation will be ...

y = a(x +4)^2 +7

The value of 'a' can be found from the other given point:

8 = a(-3+4)^2 +7

1 = a

So, the equation is ...

y = (x +4)^2 +7

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Please help!! i am super confused

erastovalidia [21]

Answer:

The train appears to go the same distance each minute

9mins

The cost for each person appears to be the same

Step-by-step explanation:

So for the first qu you basically want to find the distance the train travels each minute, so for

3mins : 9km

therefore

1min : 3km

basically divide 9 by 3

then the train travels 27km, how long does it take?

if 3km = 1min

then 27/3 = 9

so it takes the train 9 minutes

Then for the second qu you'll do the same thing

2ppl : $16

so one person : 16/2

so 1 person costs $8

so for 8 ppl you multiply 8 by 10

8ppl : $80

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6 0

2 years ago

The graph shows the total number of miles, y, that Miranda traveled in x hours.

algol [13]

The answer is the last one listed...
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4 0

4 years ago

Assuming x > 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s

ehidna [41]

The answer is <span>104 x times the square root of 5 x
</span>
<span>11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
</span> $11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245} *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\ \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\ \\ =11* \sqrt{5} * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\ \\ 
=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\ \\ 
=77x* \sqrt{5*x} +27x* \sqrt{5*x} = \\ \\ 
=77x \sqrt{5x} +27x \sqrt{5x} = \\ \\ 
=104x \sqrt{5x}$

4 0

3 years ago

Read 2 more answers

Help for this question fr

lesya692 [45]

Answer:

(x + 16)° = 141°

Step-by-step explanation:

Given figure is of octagon

Sum of interior angles of an octagon is 1080°

-> 5x° + 455° = 1080°

-> 5x° = 1080° - 455°

->5x° = 625°

-> x° = 625°/5

x° = 125°

x = 125

-> (x + 16)° = (125 + 16)°

-> (x + 16)° = 141°

6 0

3 years ago

18)Let f(x) = -3x + 4 and g(x) = 8x2 - 9. Find g(4) - f(4) . A)140 B)127 C)131 D)136

vazorg [7]

Answer: -127

Step-by-step explanation:

They are giving you the corresponding x value for which you should plug into the function. So plug 4 into g(x) and plug 4 into f(x). Then subtract them

g(x) = -3(4) + 4 = -8

Im assuming that is $8x^2$

f(x) = 8(4)^2 - 9 = 119

Now do -8 - 119 to get -127

6 0

3 years ago

Read 2 more answers