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7nadin3 [17]
3 years ago
13

A civic group is selling bumper stickers as a fundraiser. During the first week, they sold 500 bumper stickers. During the secon

d week, they sold 50% more bumper stickers than the first week. During the third week, they sold 50% fewer bumper stickers than the second week.
Explain how you can use proportions to find the percent decrease from the first weeks' sales to the third weeks' sales. Your explanation must include the math you did to determine this. If you do not include the math and it make sense you will not get credit for this question.
Mathematics
2 answers:
UkoKoshka [18]3 years ago
8 0

Answer:

<em>The third week they sold $375 in bumper stickers</em>

Step-by-step explanation:

<u>Proportions and Percentages</u>

During the first week, the civic group sold 500 bumper stickers as a fundraiser.

During the second week. they sold 50% more bumper stickers than the first week. First, we calculate the increment of 50% of 500:

50% 500 = 50 * 500 / 100 = 250

Thus the second week they sold:

500 + 250 = 750 bumper stickers

Now we know the third week they sold 50% fewer than the second week.

Again, we calculate the 50%, but this time on the basis of 750, and not 500 bumper stickers:

50% 750 = 50 * 750 / 100 = 375

Thus the third week they sold:

$750 - $375 = $375

The third week they sold $375 in bumper stickers

Bingel [31]3 years ago
5 0

Answer:

Step-by-step explanation:

hehehehdhdnenwne

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Answer:

10 boxes in the top row.

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Step-by-step explanation:

Let n be the number of rows.

Given:

Total number of rows = 8

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Solution:

Part A:

We know that the bottom row has 38 boxes and each row has four fewer boxes than the row below it.

Using below function for determining the number of boxes in each rows.

f(n)=38-(8-n)4

Where:

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We need to find the boxes in the first row.

So, substitute n = 1 in above function.

f(1)=38-(8-1)4

f(1)=38-7\times 4

f(1)=38-28

f(1)=10

Therefore, 10 boxes in the top row.

Part B:

Total boxes in the entire display.

Using formula as given below to determine the sum of the boxes in entire display.

S_{n} = \frac{n}{2}(f(1)+f(n))

Substitute n = 8, f(1) = 10 and f(8) = 38 in the above equation.

S_{8} = \frac{8}{2}(10+38)

S_{8} = 4(48)

S_{8} = 4\times 48

S_{8} = 192\ boxes

Therefore, 192 boxes in the entire display.

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