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AlladinOne [14]
3 years ago
10

What characteristics are easily found when given a quadratic equation in Standard form and/or in vertex form?

Mathematics
1 answer:
labwork [276]3 years ago
3 0
In vertex form the value of the vertex is easily identified in the equation. I’m standard form the value of the x intercepts are evident.
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dale has a square garden. He adds a 2-foot-wide walkway around his garden. If the total area of the walkway and garden is 196 sq
dem82 [27]
Let the side of the garden alone (without walkway) be x.  
Then the area of the garden alone is x^2.  
The walkway is made up as follows:

1) four rectangles of width 2 feet and length x, and 
 2) four squares, each of area 2^2 square feet.


The total walkway area is thus x^2 + 4(2^2) + 4(x*2).  

We want to find the dimensions of the garden.  To do this, we need to find the value of x.

Let's sum up the garden dimensions and the walkway dimensions:

x^2 + 4(2^2) + 4(x*2) = 196 sq ft

x^2 + 16 + 8x = 196 sq ft

x^2 + 8x - 180 = 0

(x-10(x+18) = 0

x=10 or x=-18.  We must discard x=-18, since the side length can't be negative.  We are left with x = 10 feet.

The garden dimensions are (10 feet)^2, or 100 square feet.


4 0
3 years ago
Use complete sentences to explain why |x|+2>|x|
Anna007 [38]
The absolute value of an given number is always positive.  So, when adding two to any positive number will always be greater than the number by itself.
4 0
4 years ago
The sum of squares of two consecutive odd numbers is 514 find the numbers ​
amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

\rule{130}1

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

\rule{130}1

☯ \underline{\boldsymbol{According\: to \:the\: Question\:now :}}

:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup

When,

\bullet\: \textsf {x = } \textbf {15}

\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}

\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.

5 0
3 years ago
Easy Question giving 80 points
Bas_tet [7]

Answer:

1=30

2=90

3=21

4=39

5=39

6=24

7=24

8=66

9=66

10=21

11=60

12=120

13=60

14=120

15=48

16=105

17=27

18=129

19=51

20=129

21=51

Step-by-step explanation:

please please please pleas mark me brainliest that was really hard

5 0
3 years ago
Read 2 more answers
Samara was playing a game. She wrote down this number sentence to find the total number of points for 11 games in a row.
MissTica

Answer:

55 score in his games

Step-by-step explanation:

4 0
3 years ago
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