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Amiraneli [1.4K]
3 years ago
14

A lock has two digit numeric code, with the numbers 1 through 7 available for each digit of the code. Note that numbers can be r

epeated in the code so there are 7 possibilities for each two digits. Find the total number of possible codes for the lock.
Mathematics
1 answer:
lubasha [3.4K]3 years ago
7 0
If there is 2 digits and 7 numbers the combos would be:
1,1 2,1 3,1 4,1 5,1 6,1 7,1
1,2 2,2 3,2 4,2 5,2 6,2 7,2
1,3 2,3 3,3 4,3 5,3 6,3 7,3
1,4 2,4 3,4 4,4 5,4 6,4 7,4
1,5 2,5 3,5 4,5 5,5 6,5 7,5
1,6 2,6 3,6 4,6 5,6 6,6 7,6
1,7 2,7 3,7 4,7 5,7 6,7 7,7

Therefore there are 49 possible combinations :)
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Trapezoid MNPQ is similar to Trapezoid RSTU. What is the length of the "x" on the misside side NP ? Also, what is the length of
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Answer:

x =  15

y =  25

Step-by-step explanation:

Given

See attachment for MNPQ and RSTU

Required

Find x and y

To solve this question, we make use of equivalent ratios of corresponding side lengths.

The ratio of corresponding sides are:

MN : RS

NP : ST

PQ : TU

MQ : RU

From the attachment, we have:

MN : RS \to 18 : 30

NP : ST \to x : 25

PQ : TU \to 15 : y

To solve for x, we equate MN : RS and NP : ST

18 : 30 = x : 25

Express as fraction

\frac{18 }{ 30 }= \frac{x }{ 25}

Make x the subject

x =  25 * \frac{18 }{ 30 }

x =  \frac{25 * 18 }{ 30 }

x =  \frac{450}{ 30 }

x =  15

To solve for y, we equate MN : RS and PQ : TU

18 : 30 = 15 : y

Express as fraction

\frac{18 }{ 30 }= \frac{15 }{ y}

Make y the subject

y = 15 * \frac{30 }{ 18 }

y =  \frac{15 *30}{ 18 }

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What is a right angle degree
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Anand needs to hire a plumber. He's considering a plumber that charges an initia
Ede4ka [16]

Complete question :

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an

hourly rate of $28. The plumber only charges for a whole number of hours. Anand would like to spend no more than $250, and he wonders how many hours of work he can afford.

Let H represent the whole number of hours that the plumber works.

1) Which inequality describes this scenario?

Choose 1 answer:

A. 28 + 65H < 250

B. 28 + 65H > 250

C. 65 + 28H < 250

D. 65 +28H > 250

2) What is the largest whole number of hours that Anand can afford?​

Answer:

65 + 28H < 250

Number of hours Anand can afford = 6 hours

Step-by-step explanation:

Given the following information :

Initial hourly rate = $65

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Number of hours worked (whole number) = H

Maximum budgeted amount to spend = $250

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(Initial charge + total charge in hours) should not be more than $250

$65 + ($28*H) < $250

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Number of hours Anand can afford :

65 + 28H < 250

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28H < 185

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H < 6.61

Sinve H is a whole number, the number of hours he can afford is 6 hours

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