The given function is a variable separable differential equation. Combine like terms, integrate, apply the appropriate limits, and express V in terms of t. This is done as follows:
dV/dt = -3(V)^1/2 dV/-3V^1/2 = dt
m here is the initial V which is 225. Then after integrating,
-2/3 (√V - √225) = t -2/3 (√V - 15) = t
That is the expression for V at time t. I hope I was able to help. Have a good day.
<em>The product of an even number of negatives give us a positive number. An odd number of - 1's gives us a negative one, -1. This can be applied to any set of products. The product of an odd number of negatives give us a negative number. </em>