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Anni [7]
4 years ago
15

Evaluate if x = 2. 9x + 13 A) 5 B) 18 C) 24 D) 31

Mathematics
2 answers:
san4es73 [151]4 years ago
8 0
The Answer is

D) 31 Because 9x+13, 9(2)+13, 18+13, 31
Volgvan4 years ago
3 0

Answer:

:3  the answer is D)

Step-by-step explanation:

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6. A hospital needs a supply of an expensive medicine. Company A has the most
Anton [14]

We are required to find the total milligrams if medicine the hospital can get from the three companies.

The total quantity of medicine the hospital can get from the three companies is 2.75 milligrams

There are there companies:

Company A

Company B

Company C

Company A = 1.3 milligrams

Company A is 0.9 milligrams more than Company C's

A = 0.9 + C

1.3 = 0.9 + C

1.3 - 0.9 = C

0.4 = C

C = 0.4 milligrams

Company A is also twice the difference between the weight of

Company B's supply and Company C's

A = 2(B - C)

1.3 = 2(B - 0.4)

1.3 = 2B - 0.8

1.3 + 0.8 = 2B

2.1 = 2B

Divide both sides by 2

B = 2.1/2

B = 1.05 milligrams

Therefore,

A + B + C

= 1.3 + 1.05 + 0.4

= 2.75 milligrams

Read more:

brainly.com/question/24562139

4 0
3 years ago
Read 2 more answers
2x + 8 X-2 B In this diagram, mZACD = [?]°
Natasha_Volkova [10]

EXPLANATION:

STEPS:

1.First we have to find the partial distances in the two equations given and then find the total, but to do so we must find the value of x, then replace it in each of the equations and finally the sum will give us the total of all the magnitudes.

2.

3 0
2 years ago
Determine the measure of the third angle. * o 48° O 62° O 70° 132 180°
Ede4ka [16]

Answer:

B. 30°

Step-by-step explanation:

5 0
3 years ago
In which expression is the number 3 expressed as the coefficient of a variable
o-na [289]

Answer:

the second one that is 3y+1

8 0
3 years ago
Compute the discriminant D(x,y)D(x,y) of the function. f(x,y)=x3+y4−6x−2y2+3 f(x,y)=x3+y4−6x−2y2+3 (Express numbers in exact for
Igoryamba

Answer:

Point                Critical point

Q (2,0)                 local minimum

R (-2,1)                 Saddle

S (2,-1)                  local maximum

T ( -2,-1)                Saddle

O ( -2,0)                Saddle

Step-by-step explanation: INCOMPLETE ANSWER INFORMATION ABOUT THE POINTS ARE RARE

f(x,y) = x³ +y⁴ - 6x -2y² +3

df/dx = f´(x) = 3x² -6x

df/dxdx = f´´(xx) = 6x

df/dy = f´(y) = -4y

df/dydy = 4

df/dydx = df/dxdy = 0

df/dydy = f´´(yy)

D = [ df/dxdx *df/dydy] - [df/dydx]²

D = (6x)*4 - 0

D = 6*2*4     D > 0 and the second derivative on x is  6*2 = 12

so  D > 0 and df/dxdx >0  there is a local minimum in P

Q(2,1)

D = (6*2)*4  D>0  and second derivative on x is 6*2

The same condition there is a minimum in Q

R ( -2,1)

D = 6*(-2)*4 = -48  D< 0 there is a saddle point in R

S (2,-1)

D = 6*2*4 = 48  D > 0 and  df/dxdx = 6*-1  = -6

There is a maximum in S

T ( -2,-1)

D = 6*(-2)*(4) = -48  D<0 there is a saddle point in T

O ( -2,0)

D = 6*(-2)*4 = -48 D<0  there is a saddle point in O

5 0
3 years ago
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