We have 7*48=336 cans. Dividing by 8 cans per stack, we have 336/8=42 stacks.
Answer:
13
Step-by-step explanation:
-15=11-2t
Answer:
do you s still need it or not anymore for if you do I could answer
By algebraic handling, the value of k of the system of equations is equal to 2.
<h3>What are the values of two constants such that a system of equations has a single solution?</h3>
Herein we find a system formed by two equations, a linear function and a quadratic equation with the following characteristics:
y = x² + b · x + 5 (1)
y = 2 · x + b (2)
If we eliminate y in (1) and (2), then we have this expression:
x² + b · 3 + 5 = 2 · x + b
3² + b · x + 5 = 2 · 3 + b
3 · b + 14 = 6 + b
14 = 6 - 2 · b
8 = - 2 · b
b = - 4
By (2), y = k, x = 3 and b = - 4, we find the value of k:
k = 2 · 3 - 4
k = 6 - 4
k = 2
By algebraic handling, the value of k of the system of equations is equal to 2.
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Answer:
f(x) = (x + 4)(x - 4)(x + 3)
The other zeros of the function are at 4 and -3.
Step-by-step explanation:
Given function is f(x) = x³ + 3x² - 16x - 48.
Now, given that - 4 is a zero of the given function.
So, the function has a factor equals to (x + 4).
Now, f(x) = x³ + 3x² - 16x - 48
⇒ f(x) = x³ + 4x² - x² - 4x - 12x - 48
⇒ f(x) = x²(x + 4) - x(x + 4) - 12(x + 4)
⇒ f(x) = (x + 4)(x² - x - 12)
⇒ f(x) = (x + 4)(x - 4)(x + 3)
Therefore, the other zeros of the function are at 4 and -3. (Answer)