Larger pets need to be transported in larger portable kennels. Using a graphing calculator and the relationship between the widt
h, length, and height, find the dimensions of a portable kennel whose volume is 7.4 ft3. The dimensions of a portable kennel can be expressed as width x, length x + 0.4, and height x − 0.2? What are the dimensions of a portable kennel with a volume of 7.4 ft3? Use a graphing calculator to solve. Round the dimensions to the nearest tenth.
1 answer:
Answer:
- width: 1.9 ft
- length: 2.3 ft
- height: 1.7 ft
Step-by-step explanation:
The volume of a rectilinear shape is given by ...
V = W·L·H . . . . . where W, L, and H represent width, length, and height
Filling in the given information, we want to find a solution to ...
7.4 = x(x +0.4)(x -0.2)
If we write ...
f(x) = x(x +0.4)(x -0.2)
Then we're looking for the value of x that satisfies ...
f(x) -7.4 = 0
The attached graph shows that value to be 1.897, about 1.9 (feet). Then the desired kennel dimensions are ...
- width: 1.9 ft
- length: 2.3 ft
- height: 1.7 ft
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Answer:
a) Let X the random variable of interest, on this case we know that:
This random variable represent that two people have the same birthday in just one classroom
b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:
And we can find the individual probability:
And then:
And since we want the probability in the 3 classes we can assume independence and we got:
So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992
Step-by-step explanation:
Previous concepts
A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Solution to the problem
Part a
Let X the random variable of interest, on this case we know that:
This random variable represent that two people have the same birthday in just one classroom
Part b
We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:
And we can find the individual probability:
And then:
And since we want the probability in the 3 classes we can assume independence and we got:
So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992
Answer:
.
Step-by-step explanation:
The perimeter of a rectangle is the sum of it's side lengths.
A rectangle has 4 sides where it's opposite sides are congruent.
So if one side has measurement w, then there is another side that has measurement w.
If there is one side that has measurement l, then there is another side that has measurement l.
So if you add w+w+l+l you get 2w+2l.
They are giving us that the perimeter is P, so P=2w+2l.
we are being asking to solve for l.
P=2w+2l
First step: Isolate term that contains the l, so get 2l by itself first.
We are going to subtract 2w on both sides giving us:
P-2w=2l
2l=P-2w
Now that we have 2l by itself it is time to perform the last step in getting l by itself.
Second step: Divide both sides by 2.
This gives us:
l=(P-2w)/2
You may separate the fraction like so:
.
I don't know your options but I have solve for l in terms of P and w
and got .
Please let me know if you have further questions with this problem.