Question

(x+4)²-x²=0 hãy tìm x

Answer 1

Answer:

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Step-by-step explanation:

Let's solve your equation step-by-step.

$(x+4)^{2} -x^{2} =0$

Step 1: Simplify both sides of the equation.

$(x+4)^{2} -x^{2} =0$

$x^{2} +8x+16+-x^{2} =0$    (Distribute Law)

$(x^{2} + -x^{2})+(8x)+(16)=0$     (Combine Like Terms)

$8x+16=0$

$8x+16=0$

Step 2: Subtract 16 from both sides.

$8x+16-16=0-16\\8x=-16$

Step 3: Divide both sides by 8.

$\frac{8x}{8} =\frac{-16}{8}$

x=−2

Answer:

x=−2