Answer:

Step-by-step explanation:
Given

Required
Write a recursive expression

When n = 1


When n = 2

can be rewritten as

Substitute 3 for f(1)

Express 1 as 2 - 1
----- (1)
When n = 3

can be rewritten as

Substitute 8 for f(2)

Express 2 as 3 - 1
------ (2)
Write out (1) and (2)


Replace 2 and 3 with n in both cases; This gives

Hence;
The recursive is 
Answer:
smallest amount of sugar = 40 kg
largest amount of sugar = 80 kg
Step-by-step explanation:
2 : 3 : 4
2 + 3 + 4 = 9
180 ÷ 9 = 20
Therefore,
2 : 3 : 4 = (2 x 20) : (3 x 20) : (4 x 20) = 40 : 60 : 80
So the smallest amount of sugar = 40 kg
and the largest amount of sugar = 80 kg
Right answer is 1.4013841