Answer:
The answer is on the paper. Hope it's correct :)
Answer:
axis of symmetry x=3/2
vertex (3/2, 0)
Step-by-step explanation:
to find the axis of symmetry we use h = -b/2a
where ax^2 + bx+c
h = -(-12)/2(4)
h= 12/8
h = 3/2
the axis of symmetry is x = 3/2
the x coordinate of the vertex is h x=3/2
to find k, the y coordinate of the vertex, substitute x=3/2 into the equation
y=4x^2-12x+9
y=4(3/2) ^2-12(3/2)+9
= 4 (9/4) - 6*3 +9
= 9-18+9
= 0
the vertex (3/2, 0)
Answer:
9
Step-by-step explanation:
UT^2 = UV * UW
6^2 = (x - 7)(x - 7 + 5)
36 = (x - 7)(x - 2)
36 = x^2 - 2x - 7x + 14
x^2 - 9x - 22 = 0
(x - 11)(x + 2) = 0
x - 11 = 0 or x + 2 = 0
x = 11
UW = x - 7 + 5
UW = 11 - 7 + 5
UW = 9
PLEASE STOP GIVING OUT LINKKKSSSS!!!
