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Marina CMI [18]
3 years ago
14

I need help pleaseeeeee

Mathematics
1 answer:
kirill115 [55]3 years ago
6 0

ok for the first one says

f(x)= 2 which is our Y, now we see when y is 2 our x = 1

f(x)=0 so when y= 0 , x = 2

f(1) = 2

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<u>Step-by-step explanation:</u>

EQ1:   a + b + c = 2            -->       b + c = 2 - a

EQ2:  ab + bc + ac = -1     -->        b + c = (-1 - bc)/a

EQ3:  abc = -2                  -->           bc = -2/a

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2-a=\dfrac{-1-bc}{a}\\\\\\\text{Clear the denominator:}\\a(2-a)=-1-bc\\\\\text{Substitute bc:}\\a(2-a)=-1-\dfrac{-2}{a}\\\\\\\text{Clear the denominator:}\\a^2(2-a)=-a+2\\\\\\\text{Simplify and set equal to 0:}\\2a^2-a^3=-a+2\\0=a^3-2a^2-a+2\\\\\text{Factor:}\\0=a^2(a-2)-1(a-2)\\0=(a^2-1)(a-2)\\\\\text{Solve for a:}\\a^2-1=0\qquad a-2=0\\a=\pm1}\qquad \qquad  a=2

Consider the solution a = 2 and plug it into EQ1 to solve for "b"

b + c = 2 - 2

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b = -c

Plug in a = 2, b = -c, and c = c into a³ + b³ + c³

  2³ + (-c)³ + c³

= 8 - c³ + c³

= 8

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