If you place a 100-foot ladder against the top of a 96-foot building, how many feet will the bottom of the ladder be from the bo
2 answers:
Answer:
28 ft
Step-by-step explanation:
I add a graph to this question.
In the graph we can see that the ladder, the building and the distance ''x'' form a right triangle.
We can use the Pythagorean theorem to solve this exercise. The Pythagorean theorem states that if ''a'' and ''b'' are the sides of a triangle and 'h'' is its hypotenuse ⇒
If we apply this equation to the graph we can find the distance ''x'' :
We find that the distance ''x'' is 28 ft
X^2+y^2=z^2 x^2+96^2=100^2 x=sqrt(100^2-96^2) x=28 so the distance from the base of the ladder and the base of the ladder is 28ft. Hope this helps. Any questions please just ask. Thank you.
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
ΔMNL ≅ ΔQNL by ASA or AAS
by ASA
Proof:
∠ LNM = ∠LNQ =90
LN = LN {Common}
∠MLN = ∠QLN {LN bisects ∠ L}
By AAS
∠Q + ∠QLN + ∠LNQ = 180 {Angle sum property of triangle}
∠Q + 32 + 90 = 180
∠Q + 122 = 180
∠Q = 180 -122 =
∠Q = 58
∠Q = ∠M
∠MNL =∠QNL = 90
LN = LN {common side}
Answer:
bottom =80m^2
Side =50m^2
triangle = 3 ×8 ×5