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monitta
3 years ago
15

If you place a 100-foot ladder against the top of a 96-foot building, how many feet will the bottom of the ladder be from the bo

ttom of the building?

Mathematics
2 answers:
kolezko [41]3 years ago
8 0

Answer:

28 ft

Step-by-step explanation:

I add a graph to this question.

In the graph we can see that the ladder, the building and the distance ''x'' form a right triangle.

We can use the Pythagorean theorem to solve this exercise. The Pythagorean theorem states that if ''a'' and ''b'' are the sides of a triangle and 'h'' is its hypotenuse ⇒

a^{2}+b^{2}=h^{2}

If we apply this equation to the graph we can find the distance ''x'' :

x^{2}+(96ft)^{2}=(100ft)^{2}

x^{2}+9216(ft^{2})=10000(ft^{2})

x^{2}=784(ft^{2})

x=\sqrt{784(ft^{2})}

x=28ft

We find that the distance ''x'' is 28 ft

soldier1979 [14.2K]3 years ago
4 0
X^2+y^2=z^2

x^2+96^2=100^2

x=sqrt(100^2-96^2)

x=28 so the distance from the base of the ladder and the base of the ladder is 28ft.

Hope this helps. Any questions please just ask. Thank you.
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Up 2 units = y shifted up by 2:
y = x^2 + 2
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3 years ago
G(x) =2x + 4; Find g(-3)
yuradex [85]

Answer:

g(-3)=-2

Step-by-step explanation:

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Dmitriy789 [7]

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y=1/2x

Step-by-step explanation:

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2 years ago
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Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees.
Serga [27]

Answer:

Yes

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by ASA

Proof:

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∠MLN = ∠QLN     {LN bisects ∠ L}

By AAS

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∠Q + 32 + 90 = 180

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