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2 years ago

Hiiiijengniuenfhvnaefnhvadf

Mathematics

2 answers:

jekas [21]2 years ago

7 0

Answer:

iebffwkeeewbgj

Step-by-step explanation:

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Aloiza [94]2 years ago

3 0

Answer:

hiiiiieykfddhmlsaafjmxa

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9/6 divided 1/2 can somebody help please

miv72 [106K]

The answer is 3...........

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2 years ago

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Simplify a^2+ab-2b^2/a^2-2ab-3b^2

Ahat [919]

a4b2 + 2a4 - 12a3b - 2ab3 - 4b2

———————————————————————————————

2a2

8 0

3 years ago

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In the figure below, O is between M and P, and N is the midpoint of MO. If =MP16 and =NO4, find OP.

Crazy boy [7]

Answer:

O is in between m and p so it is 6

Step-by-step explanation:

In the figure below, O is between M and P, and N is the midpoint of MO. If =MP16 and =NO4, find OP.

6 0

2 years ago

In the Volume of Cylinders, Cones and Spheres section, what is the volume of a sphere with a radius of 6in? *

Rudiy27

Answer:

The volume of the sphere is 288π in³

Step-by-step explanation:

To calculate the volume of a sphere we have to use the following formula:

V = volume

r = radius

V = ⁴⁄₃πr³

V = ⁴⁄₃ * π * (6in)³

V = π * ⁴⁄₃ * 216 in³

V = 288π in³

The volume of the sphere is 288π in³

4 0

3 years ago

The graph of f(x) = x^2 has been shifted into the form f(x) = (x − h)^2 + k

stepan [7]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see, it went to the right 2 units, and then up 3 units.

that simply means, C = -2, D = 3.

8 0

3 years ago