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3 years ago

How would I graph this y=1/3x+2,y=-x-2

1 answer:

8 0

There are 2 lines.
For the first line, you would start at (0,2) then proceed to go up 1 then go to the right 3.
For the second line, you would start at (0,-2) then proceed to go down and right by 1

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2 = f/8 f= ? Pleaze helpsz me i will give you robux I promise !!

Ilia_Sergeevich [38]

Answer:

f = 16

Step-by-step explanation:

2 = f/8

Cross Multiplying, we get

f = 16

hope it helps!

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3 years ago

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Multiply and divide in scientific notation

sashaice [31]

Answer:

To multiply two numbers in scientific notation, multiply their coefficients and add their exponents. To divide two numbers in scientific notation, divide their coefficients and subtract their exponents. In either case, the answer must be converted to scientific notation.

Step-by-step explanation:

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3 years ago

Miranda has earned scores of 20, 22, 18, and 24 on her last four math quizzes. What score will she need to earn on the fifth qui

BigorU [14]

Answer:

Step-by-step explanation:

20 + 22 + 18 + 24 + 16 = 100

100/5= 2O

hopes this helps sorry for the late answer I just want others to get the correct answer.

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3 years ago

How to graph the slope for y=5x +2

Ilia_Sergeevich [38]

Answer:

see attatched image

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2 years ago

Suppose we want to choose a value of x within 3 units of 11. [This means a value of x that is less than 3 units away from 11.] T

Dahasolnce [82]

Answer:

(a) [8, 14]

(b) $8 \leq x \leq 14$

(c)See attachment

Step-by-step explanation:

We want to choose a value of x within 3 units of 11.

(a)Now, 11-3=8 and 11+3=14

The possible values of x ranges is in the closed interval [8,14]

(b) Since x is within 3 units of 11., we have:

$|11-x|\leq3$

Solving the absolute inequality

$-3 \leq 11-x \leq 3\\$In $ -3 \leq 11-x\\ x \leq 11+3\\x \leq 14\\\\$In $ 11-x \leq 3\\ 11-3 \leq x\\8 \leq x\\$Therefore,an inequality that represents all values of x that meet this constraint is:$\\8 \leq x \leq 14$

(c)To draw the number line, we use a closed dot since we have the less than or equal to sign.

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2 years ago

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