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Amiraneli [1.4K]
3 years ago
9

Alan needs to drive 400 miles to reach Madison. He is driving at a constant speed of 55 miles per hour. The function y = 400 − 5

5x represents Alan’s distance in miles from Madison in terms of the number of hours he drives. Andrew is also driving at a constant speed to reach Madison. The table represents Andrew’s distance in miles from Madison in terms of the number of hours he drives.
Which statements about this situation are true?
A. Alan is driving at a faster speed.
B. Andrew is driving at a faster speed.
C. Alan and Andrew are driving at the same speed.
D. Alan was farther away from Madison when he started driving.
E. Andrew was farther away from Madison when he started driving.
F. Alan and Andrew started the same distance from Madison.
Mathematics
1 answer:
harkovskaia [24]3 years ago
3 0

At a constant speed Alan is traveling 7.27 repeating.


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HELP!!! PLEASE!!!!
Makovka662 [10]

Answer:

  • y = 2x² - 5x + 7

Step-by-step explanation:

For this problem, imagine the standard form, which is:

f(x) = ax² + bx + c = y

Using the table, and adding that y at the end, we can plug in and write out the following equations. (<em>Writing it out is important</em>):

f(-1) = a(-1)² + b(-1) + c = 14

f(0) = a(0)² + b(0) + c = 7

f(1) = a(1)² + b(1) + c = 4

f(2) = a(2)² + b(2) + c = 5

Now if this doesn't look familiar, it's actually a <u>systems of equations</u> using the a, b, and c elements as your three variables! If you simplify the equations:

f(-1) = a - b + c = 14

f(0) = c = 7

f(1) = a + b + c = 4

f(2) = 4a + 2b + c = 5

Something unique just happened. We have already defined what ' c ' is!

<u><em>c = 7</em></u>

Setting that aside, if you remove the f(x) portion of the equations, you're left with:

a - b + c = 14

a + b + c = 4

4a + 2b + c = 5

Using the two upper equations, if we add them together (you can do that as it doesn't change the values of the variables) you get:

2a + 2c = 18

Note: the ' b ' variables cancelled out in the addition [ b +  (-b) ]

If you further simplify the equation:

a + c = 9

Awesome. Now we already know that <u>c = 7</u>, so if you plug that into the equation:

a + 7 = 9

Solve for a. So then a = 2

Now that we know the following:

a = 2

c = 7

We can then use the equation:

a + b + c = 4

And solve for b!

2 + b + 7 = 4

Simplify.

b + 9 = 4

Simplify.

b = -5

Now at this point, since you know what a, b and c are, you can write the equation!

f(x) = 2x² - 5x + 7

You can confirm your work by putting any of the x values in the table through!

4 0
3 years ago
Read 2 more answers
Find height of triangle given hypotenuse and angle
harkovskaia [24]
Given h is the height, H is the hypotenuse and A is the base angle,
then Sin(A) = h/H
so h = HSin(A)
7 0
4 years ago
2. If ¡2x+3 = i, where i = V-1, then which of the
Alexus [3.1K]

I assume you mean the equation

i^{2x+3} = i

Since i = √(-1), we have i⁴ = 1 and so i⁵ = i. Then 2x + 3 must be some multiple of 5.

Now just check for which of the given choices that this holds:

x = 16   ⇒   2x + 3 = 35   (yes)

x = 11   ⇒   2x + 3 = 25   (yes)

x = 10   ⇒   2x + 3 = 23   (no)

x = 14   ⇒   2x + 3 = 31   (no)

6 0
3 years ago
Differentiate the function with respect to x<br> f(x)= x^4/ x^2- 4<br> Show work
jeyben [28]

Answer:

Step-by-step explanation:

f(x)=\frac{u}{v} ,u~ and~ v~ functions~ of~ x\\f'(x)=\frac{v ~u'-u~v' }{v^2} \\f(x)=\frac{x^4}{x^2-4} \\f'(x)=\frac{(x^2-4)*4x^3-x^4(2x)}{(x^2-4)^2} \\=\frac{2x^3(2x^2-8-x^2) }{(x^2-4)^2} \\=\frac{2x^3(x^2-8)}{(x^2-4)^2}

7 0
3 years ago
5.
shutvik [7]
What’s the question? Lol
7 0
3 years ago
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