Calculate the mass of 20.0 moles of He (in g)
1 answer:
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The answer for the following problem is described below.
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Explanation:
Given:
enthalpy of combustion of glucose(Δ of
) =-1275.0
enthalpy of combustion of oxygen(Δ of
) = zero
enthalpy of combustion of carbon dioxide(Δ of
) = -393.5
enthalpy of combustion of water(Δ of
) = -285.8
To solve :
standard enthalpy of combustion
We know;
Δ = ∈Δ
(products) - ∈Δ
(reactants)
(s) +6
(g) → 6
(g)+ 6
(l)
Δ = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]
Δ = [6 (-393.5) + 6(-285.8)] - [0 - 1275]
Δ = 6 (-393.5) + 6(-285.8) - 0 + 1275
Δ = -2361 - 1714 - 0 + 1275
Δ =-2800 kJ
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Answer : The chronological order events related to the formation of the universe with the stages in which they occurred are given below;
- Expansion from an infinitely hot point - Which is also called as the Planck era from which the big bang theory arrived. It is assumed that from the moment of initial expansion to
seconds afterwards, and many also refer that it was from an infinitely hot point.
- Hydrogen fuses into helium - This was called as the era of Nucleosynthesis which resulted from the Fusion and it continued in the Era of Nucleosynthesis ( which is 0.001 seconds – 3 minutes)
- The first neutral atom begins to form - Era of atoms, it began in around 380,000 years – 1 billion years or so.
For better understanding please refer the attachment.
Answer:
Explanation:
Hello!
In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:
Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.
Best regards!
Answer:
Explanation:
From the question we are told that:
Edge length of the unit cell
a)
Generally the equation for The relationship between edge length and radius is mathematically given by
Therefore
b)
From the question we are told that:
Density
Edge length of
Therefore Volume is given as
Generally the equation for Mass is mathematically given by
Therefore Molarity is given as
Finally The atoms in a unit cell is