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2 years ago

30. What is the solution to the system of equations?

Mathematics

1 answer:

sukhopar [10]2 years ago

5 0

Answer:

x = 3

y = 0

z = 8

Step-by-step explanation:

a) 3x + 3y - z = 1

b) z = 8

c) -x -3y + 2z = 13

a) 3x + 3y - 8 = 1 (substitution)

a) 3x + 3y = 9

c) - x - 3y + 2(8) = 13 (substitution)

c) -x - 3y + 16 = 13

c) -x - 3y = -3

(3x + 3y = 9) + (-x -3y = -3)

= 2x = 6

x = 3

a) 3(3) + 3y - 8 = 1

9 + 3y - 8 = 1

y = (1 -9 + 8)/3

y = 0

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2 years ago

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hichkok12 [17]

Answer:

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3 years ago

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2 years ago

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vitfil [10]

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3 years ago

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

3 years ago