Answer:
a) Attached
b) P=0.60
c) P=0.80
d) The expected flight time is E(t)=122.5
Step-by-step explanation:
The distribution is uniform between 1 hour and 50 minutes (110 min) and 135 min.
The height of the probability function will be:
Then the probability distribution can be defined as:
![f(t)=\frac{1}{25}=0.04 \,\,\,\,\\\\t\in[110,135]](https://tex.z-dn.net/?f=f%28t%29%3D%5Cfrac%7B1%7D%7B25%7D%3D0.04%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%5C%5C%5Ct%5Cin%5B110%2C135%5D)
b) No more than 5 minutes late means the flight time is 125 or less.
The probability of having a flight time of 125 or less is P=0.60:
c) More than 10 minutes late means 130 minutes or more
The probability of having a flight time of 130 or more is P=0.80:
d) The expected flight time is E(t)=122.5
Dog No dog Total
Cat 31 10 41
No cat 24 7 31
Total 55 17 144
Answer:
The diagonal is about 14 m
Step-by-step explanation:
A = s^2
98 = s^2
so
s = √98
diagonal c^2 = 98 + 98
c^2 = 196
c = √196
c ≈ 14
Answer:
The diagonal is about 14 m
<h2><u>ANSWER</u></h2><h3>UX+RX=W</h3><h3>LETS TAKE X COMMON</h3><h3>X(U+R)=W</h3><h3>X=W/(U+R)</h3>
Answer:
Step-by-step explanation:
Since interest is compounded semi-annually (half a year or 6 months), in a spawn of 2 years, the interest will have been compounded 4 times. As given in the problem, each time the interest is compounded, the new balance will be 107% or 1.07 times the amount of the old balance.
Therefore, we can set up the following equation to find the new balance after 2 years:
