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nlexa [21]
3 years ago
6

Divide. write in smplest form 12÷2 2/7

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0
I hope this helps you

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Suppose that circles A and B have a central angle measuring 100°. Additionally, the measure of the sector for circle A is 10π m2
34kurt
12 m

<span><span>10π</span><span>40π</span></span><span> = </span><span><span>62</span><span>x2</span></span>
x = 12

<span>When </span>circles<span> have the same </span>central<span> angle measure, the </span>ratio<span> of measure of the </span>sectors<span> is the same as the </span>ratio<span> of the radii </span>squared<span>.</span>
3 0
3 years ago
Read 2 more answers
5. Laney is 4 feet 8 inches tall. There are 2.54
Ede4ka [16]
The answer is C :) :)
6 0
3 years ago
Two college roommates have each committed to donating to charity each week for the next year. The roommates’ weekly incomes are
schepotkina [342]

Answer:

C. 5 weeks.

Step-by-step explanation:

In this question we have a random variable that is equal to the sum of two normal-distributed random variables.

If we have two random variables X and Y, both normally distributed, the sum will have this properties:

S=X+Y\\\\\ \mu_S=\mu_X+\mu_Y=30+60=90\\\\\sigma_S=\sqrt{\sigma_X^2+\sigma_Y^2}=\sqrt{10^2+20^2}=\sqrt{100+400}=\sqrt{500}=22.36

To calculate the expected weeks that the donation exceeds $120, first we can calculate the probability of S>120:

z=\frac{S-\mu_S}{\sigma_S} =\frac{120-90}{22.36}=\frac{30}{22.36}=1.34\\\\P(S>120)=P(z>1.34)=0.09012

The expected weeks can be calculated as the product of the number of weeks in the year (52) and this probability:

E=\#weeks*P(S>120)=52*0.09012=4.68

The nearest answer is C. 5 weeks.

6 0
2 years ago
If a₁ = 4 and an = 5an-1 then find the value of a5.
igor_vitrenko [27]

The value of a_{5} is 2500, when a_{1}=4 and 5a_{n-1}.

Given that, a_{1}=4 and 5a_{n-1}.

We need to find the value of a_{5}.

<h3>What is an arithmetic sequence?</h3>

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Now, to find the value of a_{5} :

a_{2} =5a_{2-1}=5a_{1}=5 \times4=20

a_{3} =5a_{3-1}=5a_{2}=5 \times20=100

a_{4} =5a_{4-1}=5a_{3}=5 \times100=500

a_{5} =5a_{5-1}=5a_{4}=5 \times500=2500

Therefore, the value of a_{5} is 2500.

To learn more about arithmetic sequence visit:

brainly.com/question/15412619.

#SPJ1

5 0
2 years ago
Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589.
KatRina [158]
AB = AU + UB = 20x + 108 + 273 = 20x + 381

\cfrac{AU}{AB} =\cfrac{UV}{BC}    \\  \\  \cfrac{20x+108}{20x+381} =\cfrac{444}{703}   \\  \\ 703(20x+108)=444(20x+381)\\\\14060x+75924=8880x+169164 \\  \\ 14060x-8880x = 169164 - 75924 \\  \\ 5180x = 93240 \\  \\ x=93240/5180 \\  \\ x=18
5 0
3 years ago
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