If you add them together you will get 11g
we know that
If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation
we have the equation

Let's verify all the cases to determine the solution to the problem.
<u>case A)</u> point 
Substitute the values of x and y in the equation



-------> is true
therefore
The point
is a solution of the equation
<u>case B)</u> point 
Substitute the values of x and y in the equation



-------> is true
therefore
The point
is a solution of the equation
<u>case C)</u> point 
Substitute the values of x and y in the equation



-------> is not true
therefore
The point
is not a solution of the equation
<u>case D)</u> point 
Substitute the values of x and y in the equation



-------> is not true
therefore
The point
is not a solution of the equation
therefore
<u>the answer is </u>


First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
----------------------
4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2