Plssssssssssss answer for brainiest

What is the length if the height is 15 and the area is 45? *

Scrat [10]

I’m not sure but hi :)

6 0

3 years ago

HELPP please ??? I’ll appreciate it a lot .

victus00 [196]

Answer: $\sqrt{41}$

On a keyboard you would type sqrt(41)

===========================================

Work Shown:

$\text{point L} = (x_1, y_1) = (2,-1)\\\\\text{point N} = (x_2, y_2) = (7,-5)\\\\$

$d = \text{distance from L to N}\\\\d = \sqrt{ (x_1-x_2)^2 + (y_1-y_2)^2 } \ \text{ ... distance formula}\\\\d = \sqrt{ (2-7)^2 + (-1-(-5))^2 }\\\\d = \sqrt{ (2-7)^2 + (-1+5)^2 }\\\\d = \sqrt{ (-5)^2 + (4)^2 }\\\\d = \sqrt{ 25 + 16 }\\\\d = \sqrt{ 41 }\\\\$

----------

A slight alternative is to plot the point M(2,-5) to form right triangle LMN. The 90 degree angle is at point M.

The legs are of length LM = 4 and MN = 5, which are found by subtracting the x coordinates together and the y coordinates together (or you can count the spaces). From there, use the Pythagorean theorem to get the hypotenuse LN.

The distance formula is an altered version of the Pythagorean theorem.

5 0

3 years ago

Read 2 more answers

Giselle has a catering business. There is a proportional

Vanyuwa [196]

Answer:

1) The graph labeled and the ordered pairs plotted are shown in the second picture.

2) To calculate the amount of meat (in pounds) needed for a party of 75 people:

Substitute the value of the Constant of proportionality and $x=75$ into the equation $y=kx$ and then evaluate (The result is 30 pounds).

Step-by-step explanation:

<h3> The missing graph is attached.</h3>

Proportional relationships have the following form:

$y=kx$

Where "k" is the Constant of proportionality.

1) You can observe in the graph shown in the first picture this point:

$(10,4)$

So you can subsitute the coordinates of this point into $y=kx$ and solve for "k":

$4=k(10)\\\\k=\frac{4}{10}\\\\k=\frac{2}{5}$

Now you can find the amount of meat needed for 20, 30, 40, and 50 people with this procedure:

<u>For 20 people</u>

Substituting $k=\frac{2}{5}$ and $x=20$ into the equation $y=kx$ and evaluating, you get:

$y=(\frac{2}{5})(20)=8$

The ordered pair is:

$(20,8)$

<u>For 30 people</u>

Substituting $k=\frac{2}{5}$ and $x=30$ into the equation $y=kx$ and evaluating, you get:

$y=(\frac{2}{5})(30)=12$

The ordered pair is:

$(30,12)$

<u>For 40 people</u>

Substituting $k=\frac{2}{5}$ and $x=40$ into the equation $y=kx$ and evaluating, you get:

$y=(\frac{2}{5})(40)=16$

The ordered pair is:

$(40,16)$

<u>For 50 people</u>

Substituting $k=\frac{2}{5}$ and $x=50$ into the equation $y=kx$ and evaluating, you get:

$y=(\frac{2}{5})(50)=20$

The ordered pair is:

$(50,20)$

Knowing those values of "y"and having the ordered pairs, you can finish labeling the graph an plotting the ordered pairs (See the second picture.).

2) Substituting $k=\frac{2}{5}$ and $x=75$ into the equation $y=kx$ and evaluating, you can calculate the amount of meat (in pounds) needed for a party of 75 people. This is:

$y=(\frac{2}{5})(75)=30$