the world prash would be 12 times x
The answer would be 150 (aka the last one) because the formula to find the surface area of a cube is A=6a^2
Answer:
To find the x-intercept, substitute in 0 for y and solve for x.
To find the y-intercept, substitute in 0 for x and solve for y.
x-intercept(s):
(−6,0)
y-intercept(s):
(0,3)
So I would say -6 and 0 and 2 are in domain
Answer:
Option (A) and Option (E)
Step-by-step explanation:
Length of a segment between two points
and
is given by,
Length = ![\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D)
Length of the segment between J(-8, 1) and K(-5, 5) will be,
JK = ![\sqrt{(-8+5)^2+(1-5)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-8%2B5%29%5E2%2B%281-5%29%5E2%7D)
JK = ![\sqrt{9+16}](https://tex.z-dn.net/?f=%5Csqrt%7B9%2B16%7D)
JK = 5 units
Length of segment between the points P(2, 8) and Q(7, 3) will be,
PQ = ![\sqrt{(2-7)^2+(8-3)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%282-7%29%5E2%2B%288-3%29%5E2%7D)
PQ = ![\sqrt{25+25}](https://tex.z-dn.net/?f=%5Csqrt%7B25%2B25%7D)
PQ =
units
Length of segment between the points S(-3, -10) and T(3, -2) will be,
ST = ![\sqrt{(-3-3)^2+(-10+2)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-3-3%29%5E2%2B%28-10%2B2%29%5E2%7D)
ST = ![\sqrt{36+64}](https://tex.z-dn.net/?f=%5Csqrt%7B36%2B64%7D)
ST = 10 units
Therefore, Option (A) and Option (E) are the correct options.
Answer:
2304
Step-by-step explanation: