2 years ago

Idk how to do this someone help me

Mathematics

2 answers:

Vlad [161]2 years ago

4 0

I'm thinking its 4 to the 12 power but I am not completely sure on this

Romashka [77]2 years ago

3 0

Hello!

When you multiply, the exponents add, so 4^1+4^1= 4^2.

In this problem we need to multiply 4^-8 to get 4^5.When adding you must add 13 to get -8 to 5.

This means our answer is 4^13.

Hope this helps!

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2 years ago

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anzhelika [568]

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Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

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