He can write 2/3 of a page in 1/4 of an hour.
=> He can write 2/3 × 4 = 8/3 = 2 and 2/3 of a page in an hour
Answer: 2 and 2/3 of a page per hour
ok done. Thank to me :>
The modal score would be 71. 71 appears the most in the list.
Answer:
3×5×53
Step-by-step explanation:
You can use divisibility rules to find the small prime factors.
The number ends in 5, so is divisible by 5.
795/5 = 159
The sum of digits is 1+5+9 = 15; 1+5 = 6, a number divisible by 3, so 3 is a factor.
159/3 = 53 . . . . . a prime number,* so we're done.
795 = 3×5×53
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* If this were not prime, it would be divisible by a prime less than its square root. √53 ≈ 7.3. We know it is not divisible by 2, 3, or 5. We also know the closest multiples of 7 are 49 and 56, so it is not divisible by 7. Hence 53 is prime.
The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.
