Question

A coin is tossed 600times with the frequencies as:

Answer 1

Answer:

• see below

Step-by-step explanation:

Total number of trials =600.

Number of heads = 342.

Number of tails = 258

On tossing a coin,

$let \: E_1 \: and \: E_2 \: be \: the \: events \: of \: getting \: a \: head$

and of getting a tail respectively.

then,

$1) \: P \: (getting \: a \: head) = \: P \: (E_1)$

$\longrightarrow \: \frac{number \: of \: heads \: coming \: up}{total \: number \: of \: trials}$

$\longrightarrow \: \frac{342}{600} = \frac{57}{100}$

$\longrightarrow \: 0.57$

$\red{ \rule{150pt}{3pt}} \:$

$2) P (getting \: a\: tail) =P (E_2)$

$\longrightarrow \: \frac{number \: of \: tails \: coming \: up}{total \: number \: of \: trials}$

$\longrightarrow \: \frac{258}{600} = \frac{43}{100}$

$\longrightarrow \: 0.43$