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2 years ago

Given:

Mathematics

1 answer:

Naddik [55]2 years ago

4 0

Answer:

Step-by-step explanation:i solve is A△B=(A∪B)∖(B∩A)=(A∪B)∩(B∩A)c=(A∪B)∩(Bc∪Ac)=(B∪A)∩(Ac∪Bc)=(B∪A)∩(A∩B)c=(B∪A)∖(A∩B)=B△A

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3 years ago

2. Simplify ((–3)2)3

Nat2105 [25]

Answer:

-18

Step-by-step explanation:

((-3)2)3

First, you multiply -3 and 2 which equals -6

-3·2=-6

Then, you multiply -6 and 3 which equals -18

-6·3=-18

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3 years ago

What is the sign of 3x y3xy3, x, y when x>0x>0x, is greater than, 0 and y<0y<0y, is less than, 0?

kaheart [24]

Answer:

B ) Negative

Step-by-step explanation:

Given the expression 3xy

when x>0 and y<0

The value of the expression 3xy will be negative.

This is because the product of a positive and negative number will always be negative.

For illustration,

Let x=5>0 and y=-5<0

3xy=3(5)(-5)=-75

NOTE:

$-X-=+\\-X+=-\\+X+=+$

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3 years ago

What is the greatest common factor for 28,42,56

mixer [17]

14 is the largest factor

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3 years ago

Please help, and thank you!

lawyer [7]

Answer:

3. C

4. D

Step-by-step explanation:

$x^2+25=0\\x^2=-25\\x=\pm\sqrt{-25}$

Once $\sqrt{-1}=i$

$x=\pm5i$

A quadratic equation has no real roots when the discriminant ( $\Delta$ ) is negative. $\Delta$ .

Let's try all the equations:

(A)

$2x^2-7x-9=0\\\\\Delta=\sqrt{\left(-7\right)^2-4\cdot \:2\left(-9\right)}\\\Delta=\sqrt{\left(-7\right)^2+4\cdot \:2\cdot \:9}\\\Delta=\sqrt{121} \\\Delta=11$

(B)

$2x^2=7x\\2x^2-7x=0\\x(2x-7)=0\\x=0\\\text{or}\\2x-7=0\\2x=7\\\\$

$x=\frac{7}{2}$

(C)

$2x^2+7x-9=0\\\Delta = \sqrt{7^2-4\cdot \:2\left(-9\right)}\\\Delta = \sqrt{7^2+4\cdot \:2\cdot \:9}\\\Delta = \sqrt{121} \\\Delta= 11$

(D)

$2x^2-7x+9=0\\\Delta = \sqrt{\left(-7\right)^2-4\cdot \:2\cdot \:9}\\\\\Delta=\sqrt{-23} \\\Delta=\sqrt{23i}$

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3 years ago