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bagirrra123 [75]
3 years ago
11

Find x to the nearest degree 9 5

Mathematics
1 answer:
netineya [11]3 years ago
3 0

Answer:

Cos°=B/H

=5/9

=0.5

=1/2

Cos60°=1/2

Therefore, x=60°

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HELLLPPPPPPPPPPPPPPPPPPPPPPPP
ratelena [41]

Answer:

Domain: (-3,1]

Range:  [-4,0]

x-intercepts: -3, 0

y-intercepts: 0

3 0
3 years ago
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Find the distance between the points (7,23) and (3,-3), rounded to the hundredths place​
Molodets [167]

Answer:

26.31

Step-by-step explanation:

Use distance formula

d = \sqrt{(x_{2}-x_{1)^{2} + (y_{2}-y_ ^{1)^2} }  }

substitute in points and solve

d =  \sqrt{(7-3)^2 + (23-(-3))^{2} }

d = \sqrt{4^{2}+26^{2}  }

d = \sqrt{16 + 676}

d = \sqrt{692}

d = 26.30589288

d = 26.31 rounded

5 0
3 years ago
Which undefined term is used to define an angle ?
enyata [817]

Point.

<h3>Further explanation</h3>
  • This is one of the classic problems of Euclidean geometry.
  • The angle is determined by three points, we call it A, B, C, with A ≠ C and B ≠ C.  
  • We express an angle with three points and a symbol ∠. The middle point represents constantly vertex. We can, besides, give angle names only with vertices. For example, based on the accompanying image, the angle can be symbolized as ∠BAC, or ∠CAB, or ∠A.  

Types of Angles  

  • The acute angle represents an angle whose measure is greater than 0° and less than 90°.
  • The right angle is an angle that measures 90° precisely.  
  • The obtuse angle represents an angle whose measures greater than 90° and less than 180°.  
  • The straight angle is a line that goes infinitely in both directions and measures 180°. Carefully differentiate from rays that only runs in one direction.

<u>Note:</u>

Undefined terms are the basic figure that is undefined in terms of other figures. The undefined terms (or primitive terms) in geometry are a point, line, and plane.

These key terms cannot be mathematically defined using other known words.

  • A point represents a location and has no dimension (size). It is marked with a capital letter and a dot.
  • A line represent an infinite number of points extending in opposite directions that have only one dimension. It has one dimension. It is a straight path and no thickness.
  • A plane represents a planar surface that contains many points and lines. A plane extends infinitely in all four directions. It is two-dimensional. Three noncollinear points determine a plane, as there is exactly one plane that can go through these points.  
<h3>Learn more   </h3>
  1. Undefined terms are implemented to define a ray brainly.com/question/1087090
  2. Definition of the line segment brainly.com/question/909890  
  3. What are three collinear points on a line? brainly.com/question/5795008  

Keywords: the definition of an angle, the undefined term, line, point, line, plane, ray, endpoint, acute, obtuse, right, straight, Euclidean geometry

6 0
3 years ago
Read 2 more answers
Reduce to simplest form.<br> -3/4-(-1/6)
slavikrds [6]

Answer:

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator. GCD of 1 and 6 is

1 ÷ 16

Reduced fraction: 16. Therefore, 1/6 simplified to lowest terms is 1/6.

5 0
3 years ago
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A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running
Alborosie

Answer:

x_1 =2 , x_2=7

Step-by-step explanation:

Consider the revenue function given by R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

\frac{dR}{dx_1} = -10x_1-2x_2+34 =0

\frac{dR}{dx_2} = -16x_2-2x_1+116 =0

From the first equation, we get, x_2 = \frac{-10x_1+34}{2}.If we replace that in the second equation, we get

-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156

From where we get that x_1 = \frac{156}{78}=2. If we replace that in the first equation, we get

x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7

So, the critical point is (x_1,x_2) = (2,7). We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives  and check if the criteria is fulfilled in order for it to be a maximum. We get that

\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}

\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16

We have the following matrix,  

\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right].

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is (-10)\cdot (-16) - (-2)(-2) = 156>0 and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0
4 years ago
Read 2 more answers
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