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dimaraw [331]
4 years ago
11

Does this graph represent a function? Why or why not?

Mathematics
1 answer:
DedPeter [7]4 years ago
8 0

Answer: C

Step-by-step explanation: For a function, each x-coordinate corresponds to exactly one y-coordinate.

To determine whether the graph shown here

is a function, we can use the vertical line test.

The vertical line test tells us that if each x-coordinate on the graph corresponds to exactly one y-coordinate, then any vertical line that we draw on the graph should hit the graph at only one point.

For the graph show here, any vertical line that you draw with hit the graph at only one point which means it does pass the vertical line test.

So this graph is a <em>function</em>.

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Suppose you know the length of a confidence interval of a population mean is 8.4 and the sample mean (x bar) is 10. Find the ​ma
SOVA2 [1]

Answer:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X=10 represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Solution to the problem

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The sample mean \bar X is distributed on this way:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

4 0
3 years ago
55%of what number is 22
Tju [1.3M]
55% of 40 is 22

Change the percentage into a decimal by dividing it over 100:

55/100 = 0.55

Divide:

22/0.55 = 40
3 0
3 years ago
Read 2 more answers
Six copies of a book cost $90. How much does<br> each copy of the book cost?
IRINA_888 [86]
Each book costs $15. 90 divided by 6 is 15 which is also 90 over 6.
6 0
3 years ago
Read 2 more answers
For the figure​ shown, find m&lt;1.
sdas [7]

Answer:

Step-by-step explanation:

Sum of angles of a triangle = 180

So, 56 + 58 + x = 180

      114 + x = 180

         x = 116

Now ∠ 1 + ∠x = 180      [ straight line angles]

       ∠ 1 + 66 = 180

        ∠1 = 180 - 66 = 114°

OR

You can use the rule : Exterior angle = sum of 2  interior opposite angles.

56 + 58 = ∠1

114 = ∠1

8 0
3 years ago
Helppppp pleaseeeeee!!!!!’
densk [106]

Answer:

\text{(a) }\$10,080,\\\text{(b) }\$11,289.60,

Step-by-step explanation:

Since interest is compounded annually, the amount of money the account has after n years is given by y=9,000\cdot 1.12^n.

(a) After 1 year, n=1:

9,000\cdot 1.12^1=\boxed{\$10,080}

(b) After 2 years, n=2:

9,000\cdot 1.12^2=\boxed{\$11,289.60}

3 0
3 years ago
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