So we see that the ratio between the two octagons is 7:1, since 28/4=7 so what we do next is multiply the values of the smaller octagon by 7. But that’s the long way. There’s actually a shortcut by multiplying the perimeter of the smaller octagon, 34, by 7. This in turn equals 238.

6 0

3 years ago

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The sum of two numbers is twenty-four. The difference of the two numbers is four.

RSB [31]

Answer:

$x + y = 24$

$x - y = 4$

Now, add these two equations.

You get,

$2x = 28$

$x = \frac{28}{2}$

$x = 14$

Given,

$x + y = 24$

$14 + y = 24$

$y = 24 - 14$

$y = 10$

You can test this to the other equation as well.

$x - y = 4$

$14 - 10 = 4$

Hence, the two numbers are 14 and 10.

3 0

3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$

3 0

3 years ago

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Can you help me with part b of problem 25

neonofarm [45]

C is the correct answer for the problem hope it helps :)

6 0

3 years ago