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Vinil7 [7]
3 years ago
7

Find the sum of the first 8 terms of the following series, to the nearest integer. 36, 30,25,...

Mathematics
1 answer:
givi [52]3 years ago
6 0
1288991/7776


Mark brainliest please


Hope this helps you
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Can someone please help me with my hw 20 points?
Neporo4naja [7]

Answer:

The first equation; x-2y=8

Step-by-step explanation:

Hi there!

We're told that Ty wants to isolate x in one of the equations. To do so in either, he will need to use inverse operations to cancel out values and leave just x remaining on one side of the equation.

In the second equation, he would need to subtract both sides by 6y and then divide both sides by 4 to isolate x. It's a two-step process.

However, in the first equation, he only needs to add 2y to both sides to isolate x.

I hope this helps!

7 0
3 years ago
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I NEED HELP ASAP GEOMETRY 10TH GRADE
kap26 [50]

Answer:

4

Step-by-step explanation:

1. AB:BC is 1:2

2. Add the 1 and the 2

(3)

3. Find the distance between -7 and 26

26-(-7) = 33

4. Divide the distance by 3

33/3 = 11

5. Find the distance from A---->B

-7 + 11 = 4

6 0
2 years ago
Can someone help me pls,really need help with this.ty:)
Inessa [10]
F because I had a question like that
8 0
3 years ago
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−5y+8x=−18<br> 5y+2x=58<br> ​
grin007 [14]
[1] -5y + 8x = -18
[2] 5y + 2x = 58
7 0
3 years ago
Find the sum of the infinite geometric series: 5-(5)/(3)+(5)/(9)-(5)/(27)...
Yuki888 [10]
Denote the nth partial sum of the series by

S_n=5-\dfrac53+\dfrac59-\dfrac5{27}+\cdots+5\left(-\dfrac13\right)^{n-1}+5\left(-\dfrac13\right)^n

Multiplying both sides by -\dfrac13, we have

-\dfrac13S_n=-\dfrac53+\dfrac59-\dfrac5{27}+\cdots+5\left(-\dfrac13\right)^n+5\left(-\dfrac13\right)^{n+1}

Subtracting the second equation from the first gives

S_n-\left(-\dfrac13\right)S_n=5-5\left(-\dfrac13\right)^{n+1}
\dfrac43S_n=5-5\left(-\dfrac13\right)^{n+1}
S_n=\dfrac{15}4\left(1-\left(-\dfrac13\right)^{n+1}\right)

As n\to\infty, the geometric term approaches 0, leaving you with

S_\infty=\dfrac{15}4
8 0
3 years ago
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