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Mashcka [7]
3 years ago
13

Solve for x. Round to the nearest tenth of a degree, if necessary.

Mathematics
1 answer:
Ahat [919]3 years ago
3 0
I did this last year the answer is 9.5
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Select "Rational" or "Irrational" to classify each number. 0.25 Sq. Rt. 0.25 Sq. Rt. 0.33
kolezko [41]
0.25: Rational
√0.25: Rational (=0.5)
√0.33: Irrational
8 0
3 years ago
Which of the following is the expansion of (2m - n)7?
stealth61 [152]
<span>(2m - n)</span>⁷ can be expanded using the binomial theorem or pascal's triangle, but writing out the work is proving to be really difficult. the application of the theorem is pretty complicated and it isn't easy to format in this textbox.

the expansion of this would be 128m⁷ - 448m⁶n + 672m⁵n² - 560m⁴n³ + 280m³n⁴ - 84m²n⁵ + 14mn⁶ - n⁷. let me know if you're genuinely lost on how to find it and i'll give a written explanation a shot, but i'd really, really encourage you to refer back to your notes if you took any in class (or the lesson, if it's an online class) and see if you can find anything which explains the binomial theorem or pascal's triangle. both of those will help you immensely.
6 0
4 years ago
Read 2 more answers
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
aev [14]

Answer: (B) -625

<u>Step-by-step explanation:</u>

Given the sequence {-500, -100, -20, -4, -0.8, ... }, we know that that the first term (a) is -500 and the ratio (r) is \dfrac{-100}{-500}=\dfrac{1}{5}

Input those values into the Sum formula:

S_n=\dfrac{a(1-r^n)}{1-r}\\\\S_8=\dfrac{-500\bigg(1-\dfrac{1}{5}^n\bigg)}{1-\dfrac{1}{5}}\\\\.\quad=\dfrac{-500\bigg(1-\dfrac{1}{390,625}\bigg)}{\dfrac{4}{5}}\\\\.\quad=\dfrac{-500\bigg(\dfrac{390,624}{390,625}\bigg)}{\dfrac{4}{5}}\\\\.\quad=\dfrac{5(-500)(390,624)}{4(390,625)}\\\\.\quad=-624.998\\\\.\quad=-625\quad \text{(rounded to 2 decimal places)}

4 0
4 years ago
What is the coefficient of x in 2x+3?<br><br>Please answer?
DaniilM [7]

Answer:

coefficient of x is 2

Step-by-step explanation:

genshin impact is the bestt

3 0
2 years ago
Read 2 more answers
X-5For the function g(x) =solve the following inequality.7X+7g(x) &gt; 0
iren2701 [21]
g(x)=\frac{x-5}{x+7}

We need to find the points x where

\frac{x-5}{x+7}>0

This can only happens if both, the numerator and the denominator have the same sign, that is

\begin{gathered} x-5>0 \\ x>5 \\ \text{and} \\ x+7>0 \\ x>-7 \end{gathered}

or

\begin{gathered} x-5

The first pair of inequalities leads to the set

(5,\infty)\cap(-7,\infty)=(5,\infty)

and the second

(-\infty,5)\cap(-\infty,-7)=(-\infty,7)

Then, the answer is

(-\infty,-7)\cup(5,\infty)

7 0
2 years ago
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