It would be nonsense, as if the beetle were at normal size, then it would be considered 1/1 as a scale. If you wanted to increase it, you would increase the numerator.
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
Step-by-step explanation:
given that on a six-question multiple-choice test there are five possible answers for each question, of which one is correct and four are incorrect
By mere guessing probability for choosing correct answer = p = 0.2
also each question is independent of the other
Hence if X is the number of correct questions then
X is binomial with p = 0.2 and n = 6
a) being correct on three questions,
=
(b) being correct on four questions,
= 
(c) being correct on all six questions
=
We have
that
Cost
use of a backhoe----------------------$300 an hour
<span> Estimate for equipment rental each week---------------------$18,400</span>
Total
hours operator per week--------------------------------------40
<span> 40*300</span>=$12000---------------------it
is the cost per week to use a backhoe
$12000<$18400 is ok
<span> The maximum of hours that I can rent </span>a backhoe <span> are 40 hours, since it is the limit of the
operator and it do not overcome the total budget </span>
Answer:
720
Step-by-step explanation:
nPk = n!/(n-k)!
10P3 = 10!/(10-3)! = 10!/7!
= 10·9·8 = 720
