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viktelen [127]
2 years ago
8

Solve: |2(x-5)|+11=17​

Mathematics
1 answer:
Otrada [13]2 years ago
6 0

Answer:

Step 1

Use the distributive property to multiply 22 by x-5x−5.

|2x-10|+11=17∣2x−10∣+11=17

Hint

Expand using distributive property.

Step 2

Subtract 1111 from both sides.

|2x-10|=17-11∣2x−10∣=17−11

Step 3

Subtract 1111 from 1717 to get 66.

|2x-10|=6∣2x−10∣=6

Hint

Subtract one term from another.

Step 4

Use the definition of absolute value.

2x-10=62x−10=6 2x-10=-62x−10=−6

Step 5

Add 1010 to both sides of the equation.

2x=162x=16 2x=42x=4

Step 6

Divide both sides by 22.

x=8x=8 x=2x=2

Solution

x=2x=2

x=8x=8

Step-by-step explanation:

pa brainliest

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8 0
3 years ago
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Step-by-step explanation:

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NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z​
Roman55 [17]

Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

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\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

6 0
1 year ago
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Answer:

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