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vovangra [49]
3 years ago
14

Pls help I don’t understand

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0

The answer is c. \frac{46}{9}

a. \frac{11}{5}=2.2 (2.2≠5.11) (2.2 is not equal to 5.11)

b. 5\frac{1}{8}=\frac{5}{8} or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)

c. \frac{46}{9} =5.11 (5.11=5.11) (5.11 is equal to 5.11)

Therefore c is the answer

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What is the range of the given function?
tensa zangetsu [6.8K]

Answer:

{y | y = 9, 0, - 7, - 1}

Step-by-step explanation:

Range = y coordinates = {y | y = 9, 0, - 7, - 1}

6 0
2 years ago
Eight percent of all college graduates hired by companies stay with the same company for more than five years. The probability,
Maurinko [17]

Answer:

0.1662 = 16.62% probability that exactly 2 will stay with the same company for more than five years

Step-by-step explanation:

For each graduate, there are only two possible outcomes. Either they stay for the same company for more than five years, or they do not. Graduates are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Eight percent of all college graduates hired by companies stay with the same company for more than five years.

This means that p = 0.08

Sample of 11 college graduates:

This means that n = 11

The probability, rounded to four decimal places, that in a random sample of 11 such college graduates hired recently by companies, exactly 2 will stay with the same company for more than five years is: the absolute tolerance is +-0.0001

The tolerance means that the answer is rounded to four decimal places.

The probability is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{11,2}.(0.08)^{2}.(0.92)^{11} = 0.1662

0.1662 = 16.62% probability that exactly 2 will stay with the same company for more than five years

4 0
3 years ago
The product of two Even numbers
krek1111 [17]

The product of two even numbers is even.

 

Let m and n be any integers so that 2m and 2k are two even numbers.

The product is 2m(2k) = 2(2mk), which is even.

 

 

Things to think about:

Why didn’t I just show you by using any two even numbers like the number 4 and the number 26?

Why did I change from "m" to "k" ? Are they really different numbers or could they be the same?

Why did I specifically say that m and k were integers?

 

The product of two odd numbers is an odd number.

Let m and k be any integers. This means that 2m+1 and 2k+1 are odd numbers.

The product is 4mk + 2m + 2k + 1 (hint: I used FOIL) which can be written as

2 ( 2mk + m + k ) + 1 which is an odd number.

3 0
3 years ago
Just some questions I need answered!<br><br> Solve 4z &gt; -6<br><br> Solve x + 19 &lt;= -5
Dmitriy789 [7]

4z>-6

divide by 4

z>-6/4

z>-3/2



x+19<= -5

subtract 19 from both side

x<= -24


7 0
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Tell whether the angles are complementary or supplementary. Then find the value of x.
zubka84 [21]
I hope this helps you

8 0
3 years ago
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