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gayaneshka [121]
3 years ago
15

What is the geometric sequence? 2,3,4.5?

Mathematics
1 answer:
kykrilka [37]3 years ago
7 0
An=a12n-1 or an=(1)2n-1
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NEED HELP!!! please:)
Dahasolnce [82]
No, Jonah is not correct. The answer is shown in the picture.

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2 years ago
A way to write numbers by showing the digits 0-9 with each digit having a place value
ExtremeBDS [4]
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4 0
2 years ago
Lizzie rolls two dice. What is the probability that the sum of the dice is:
zhenek [66]

Answer:

A.\ \dfrac{1}{3}\\B.\ \dfrac{5}{12}\\C.\ \dfrac{7}{36}\\

Step-by-step explanation:

Total outcomes possible: 36

A. Divisible by 3

Possible options are:

3, 6, 9 and 12.

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Possible outcomes for 9 are: {(3,6), (4,5), (5,4),(6,3)} Count 4

Possible outcomes for 12 are: {(6,6)} Count 1

Total count = 2 + 5 + 4 + 1 = 12

Probability of an event E can be formulated as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(A)  = \dfrac{12}{36} = \dfrac{1}{3}

B. Less than 7:

Possible sum can be 2, 3, 4, 5, 6

Possible cases for sum 2: {(1,1)}  Count 1

Possible cases for sum 3: {(1,2), (2,1)}  Count 2

Possible cases for sum 4: {(1,3), (3,1), (2,2)}  Count 3

Possible cases for sum 5: {(1,4), (2,3), (3,2),(4,1)}  Count 4

Possible cases for sum 6: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

Total count = 1 + 2 + 3 + 4 + 5 = 15

P(B)  = \dfrac{15}{36} = \dfrac{5}{12}

C. Divisible by 3 and less than 7:

P(A \cap B) = \dfrac{n(A\cap B)}{\text{Total Possible outcomes}}

Here, common cases are:

Possible outcomes for 3 are: {(1,2), (2,1)} Count 2

Possible outcomes for 6 are: {(1,5), (2,4), (3,3), (5,1),(4,2)} Count 5

P(A \cap B) = \dfrac{7}{\text{36}}

5 0
2 years ago
When x^3 + kx^2 − 4x + 2 is divided by x + 2 the remainder is 26, find k.
Elis [28]

Answer:

k = 6

Step-by-step explanation:

3 0
2 years ago
2800 ml +2.6 L<br> 2800 ml +2.6 L
Tom [10]

Answer:

10 800 ml

Step-by-step explanation:

I hope this helps :}

5 0
3 years ago
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