Answer:
The mean is 39
The median is 42
Step-by-step explanation:
The median is the best measure of center for the above data because half of the values are less than the median and half of the values are more than the median. It's probably the best measure of center to use in a skewed distribution.
The measure of variability is the range because is the simplest measure of variability to calculate but can be misleading if the dataset contains extreme values.
The variability is 67.25
This is how I did it
D = P - 2.50
D is price after coupon is used, P is price before
Subtract 14 from 15.96 to find the increase.
15.96 - 14 = 1.96
Divide 1.96 by 14.
1.96 / 14 = 0.14
In percents that is 14%.
This is an increase of 14%.
Hope this helps!
Answer:
65,520
Step-by-step explanation:
hope this is helpful
So basically function of m (f(m) or in this case C(m)) means the price
so just input the value you put for m for all the other m's in the problem
ex. if you had f(x)=3x and you wanted to find f(4) then you replace and do f(3)=3(4)=12 so f(3)=12 and so on
A. cost of 75 sewing machines
75 is the number you replace m with
C(75)=20(75)^2-830(75)+15,000
simplify
20(5625)-62250+15000
112500-47250
65250
the cost for 75 sewing machines is $65,250
B. we notice that in the equation, that the only negative is -830m
so we want anumber that will be big enough to make -830m destroy as much of the other posities a possible
-830m+20m^2+15000
try to get a number that when multiplied by 830, is almost the same amount as or slightly smaller than 20m2+15000 so we do this
830m<u><</u>20m^2+15000
subtract 830m from both sides
0<u><</u>20m^2-830m+15000
factor using the quadratic equation which is
(-b+ the square root of (b^2-4ac))/(2a) or (-b- the square root of (b^2-4ac))/(2a)
in 0=ax^2+bx+c so subsitute 20 for a and -830 for b and 15000 for c
you will get a non-real result I give up on this meathod since it gives some non real numbers so just guess
after guessing and subsituting, I found that the optimal number was 21 sewing machines at a cost of 6420
