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3 years ago

Solve 44>7+s+26 pls!!!!!

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

7 0

44 > 7+s+26
44 > s + 33
11 > s
or
s < 11

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P(x) = 3x + 4 q(X) = 2x^2 Find a(p(x))

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Answer:

Step-by-step explanation:

ap/2

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4 years ago

What is 696 divided by 12 and show your work please

Vinil7 [7]

Answer:

696/12

696/12 math problems division = 58. Therefore 58 to 2 decimal places= 58

696/12 divided by 2 » (696/12) ÷ 2 » 58 ÷ 2 = 29

Step-by-step explanation:

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4 0

3 years ago

Find 50% of 152: Find 25% of 152: Find 75% of 152:

Maslowich

I think:
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6 0

3 years ago

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One more than four times a number b is 17

Alinara [238K]

i guess i got the answer ...

well..... four times a number b = 4×b = 4b

one more than is +1

and this = 17

now we need to put it all together and forma an equation .... so .. it will be

4b + 1 = 17

4b = 17 - 1

4b = 16

b = 16/4

∴ b = 4

6 0

4 years ago

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Simplify the first trigonometric expression by writing the simplified form in terms of the second expression (1/1-cosx)-(cos/1+c

garik1379 [7]

$(\frac{1}{1-cos(x)})-(\frac{cos(x)}{1+cos(x)})$

cscx is 1/sinx

maybe they want us to use pythagorean identity

$cos^2(x)+sin^2(x)=1$

I notice we have 1-cos(x) and 1+cos(x), if we multiply them, we get $1-cos^2(x)$

and if we look at the pythagorean identity and minus cos^2(x) from both sides, we get

$sin^2(x)=1-cos^2(x)$

since $csc(x)=\frac{1}{sin(x)}$ , $csc^2(x)=\frac{1}{sin^2(x)}=\frac{1}{1-cos^2(x)}$

(recall that (a-b)(a+b)=a²-b²)

match the denomenators of the original fraction

multiply first fraction by $\frac{1+cos(x)}{1+cos(x)}$ and the 2nd by $\frac{1-cos(x)}{1-cos(x)}$

$(\frac{1+cos(x)}{1-cos^2(x)})-(\frac{cos(x)(1-cos(x))}{1-cos^2(x)})=$

$((csc^2(x))(1+cos(x)))-((csc^2(x))(cos(x)-cos^2(x)))=$

$csc^2(x)+csc^2(x)cos(x)-(csc^2(x)cos(x)-csc^2(x)cos^2(x)=$

$csc^2(x)+csc^2(x)cos(x)-csc^2(x)cos(x)+csc^2(x)cos^2(x)=$

$csc^2(x)+csc^2(x)cos^2(x)=$

$csc^2(x)(1+cos^2(x))$ , hmm, to get ride of those cos(x)

look to the pythagorean identity again

$sin^2(x)+cos^2(x)=1$ , force one side into form 1+cos^2(x)

$1+cos^2(x)=2-sin^2(x)$ , recall that since csc(x)=1/sin(x), sin(x)=1/csc(x) and sin^2(x)=1/(csc^2(x))

$1+cos^2(x)=2-\frac{1}{csc^2(x)}$

subsituting

$csc^2(x)(1+cos^2(x))=$

$(csc^2(x))(2-\frac{1}{csc^2(x)})=$ distributing

$2csc^2(x)-\frac{csc^2(x)}{csc^2(x)}=$

$2csc^2(x)-1$ is the simplified expression

8 0

3 years ago