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sdas [7]
3 years ago
10

a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or

an equation to show how you computed the scale drawing lengths.
Mathematics
1 answer:
faust18 [17]3 years ago
8 0

Answer:

a rectangular pool in your friend's yard is 150  x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or an equation to show how you computed the scale drawing lengths.a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or an equation to show how you computed the scale drawing lengths.a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or an equation to show how you computed the scale drawing lengths.a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or an equation to show how you computed the scale drawing lengths.a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or an equation to show how you computed the scale drawing lengths.a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or an equation to show how you computed the scale drawing lengths.a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or an equation to show how you computed the scale drawing lengths.a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or an equation to show how you computed the scale drawing lengths.a rectangular pool in your friend's yard is 150 ft x 400 ft. Create a scale drawing with a scale factor of 1/600. Use a table or an equation to show how you computed the scale drawing lengths.

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0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287

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Step-by-step explanation:

The estimated proportion of interest is \hat p=0.45

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value is:

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